Question

In: Statistics and Probability

A park claims that the average number of visitors per day is about 85. We monitor...

A park claims that the average number of visitors per day is about 85. We monitor the park on 6 random days and find the following number of visitors on these days: 46, 79, 73, 90, 80, 55 Can we conclude at ? = 0.05 that the mean number of visitors per day in general is different from 85?

Solutions

Expert Solution


Related Solutions

The average claims to an insurance company is 3 claims per day. a. Find what is...
The average claims to an insurance company is 3 claims per day. a. Find what is the probability that in a week there will be at least 5 days, 2 or 3 or 4 demands. b. Determine the probability that in a month, at least 15 days and at most 22 days, the number of demands this between 3 and 6 demands.
Statistic Q4 (a) On a sunny day, a theme park had 1,000 visitors. According to the...
Statistic Q4 (a) On a sunny day, a theme park had 1,000 visitors. According to the attendance record, 800 visitors took a ride on the roller coaster; 450 visitors took a ride on the merry-go-round. It is estimated that among those visitors who took a ride on the roller coaster, 40% of them also took a ride on the merry-go-round. A visitor on that day is selected at random. i. What is the probability that this visitor rode on both...
Park Acreage A state executive claims that the average number of acres in western Pennsylvania state...
Park Acreage A state executive claims that the average number of acres in western Pennsylvania state parks is less than 2000 acres. A random sample of 12 parks is selected, and the number of acres is shown. 2075 2065 2174 1934 2265 1936 2277 1968 2183 2029 1976 2151 a. At = 0.01, is there enough evidence to support the claim? Use the P-value method b. Find the 99% confidence interval of the true mean.
A bank manager claims that the median number of customer per day is no more than...
A bank manager claims that the median number of customer per day is no more than 440. A teller doubts the accuracy of this claim. The number of bank customers per day for 16 randomly selected days are listed below 410, 416, 416, 420, 430, 433, 437, 440, 450, 455, 455, 460, 463, 465, 465, 470 At the 0.05 significance level, test the bank manager's claim. The test statistic x is______ The x-critical value is________
A medical investigator claims that the average number of infections per week at a hospital in...
A medical investigator claims that the average number of infections per week at a hospital in Southwestern Pennsylvania is 16.3. A random sample of 12 weeks had a mean number of 17.7 infections per week with a standard deviation of 1.8 infections per week. Use a 1% significance level to test the investigator’s claim that the mean number of infections per week is 16.3. Students will need to utilize the excel functions: t.dist(), t.dist.2t(), and t.dist.rt() in this activity. Fill...
A medical investigation claims that the average number of infections per week at a hospital in...
A medical investigation claims that the average number of infections per week at a hospital in Pennsylvania is at least 19.1. A random sample of 40 weeks had a mean number of 17.7 infections, and a sample standard deviation is 3.8. Is there enough evidence to reject the investigator’s claim? Use a 8 % level of significance to test this claim.
A telephone company claims the average number of phone calls made every day in a household...
A telephone company claims the average number of phone calls made every day in a household is more than three. A random sample of 169 days is survey in a mean of two and a standard deviation of .2 are found, test the claim at a 5% level of significance. Assume the district distribution is normal.
A recent study claims that business travelers spend an average of $39 per day on meals....
A recent study claims that business travelers spend an average of $39 per day on meals. A sample of 15 business travelers found that they had spent an average of $42 per day with a standard deviation of $3.78. If alpha =0.05, what is the claim, should we reject H0 or fail to reject H0, what is the test value, what is the alternate hypothesis?
1- Assume that visitors of a hotel on average pay $20 for minibar per night per...
1- Assume that visitors of a hotel on average pay $20 for minibar per night per room, with a standard deviation of $3. Assume further that minibar expenses are normally distributed. a- What percentage of rooms are expected to pay more than $25 per night, i.e. P(x > 25) b- What percentage of rooms are expected to pay more than $40 per night, i.e. P( x > 40)? c- What percentage of rooms are expected to pay less than $12...
The average number of miles a person drives per day is 24. A researcher wishes to...
The average number of miles a person drives per day is 24. A researcher wishes to see if people over age 60 drive less than 24 miles per day. She selects a random sample of27 drivers over the age of 60 and finds that the mean number of miles driven is 22.2. The population standard deviation is miles 3.7. At a=0.05, is there sufficient evidence that those drivers over 60 years old drive less than 24 miles per day on...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT