In: Statistics and Probability
A medical investigation claims that the average number of infections per week at a hospital in Pennsylvania is at least 19.1. A random sample of 40 weeks had a mean number of 17.7 infections, and a sample standard deviation is 3.8. Is there enough evidence to reject the investigator’s claim? Use a 8 % level of significance to test this claim.
Solution :
Given that,
Population mean = = 19.1
Sample mean = = 17.7
Sample standard deviation = s = 3.8
Sample size = n = 40
Level of significance = = 0.08
This is a left (One) tailed test,
The null and alternative hypothesis is,
Ho: 19.1
Ha: 19.1
The test statistics,
t = ( - )/ (s/)
= ( 17.7 - 19.1 ) / ( 3.8 / 40 )
= -2.33
P- Value = 0.0125
The p-value is p = 0.0125 < 0.08, it is concluded that the null hypothesis is rejected.
Conclusion :
It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the average number of infections per week at a hospital in Pennsylvania is at least 19.1. at the 0.08 significance level.