In: Statistics and Probability
Let X be the exam grade of a student taking Calculus 1 with Professor Smith. The professor believes that X has a mean of 76 and a standard deviation of 12.5. Suppose there are 100 students in Professor Smith's class. Approximate the probability that X is between 73.8 and 77.8.
Solution :
Given that,
mean =
= 76
standard deviation =
= 12.5
n = 100
=
= 76
=
/
n = 12.5 /
100 = 1.25
P(73.8 <
< 77.8)
= P[(73.8 - 76) /1.25 < (
-
)
/
< (77.8 - 76) / 1.25)]
= P(-1.76 < Z < 1.44)
= P(Z < 1.44) - P(Z < -1.76)
Using z table,
= 0.9251 - 0.0392
= 0.8859