In: Statistics and Probability
Define random variable X : time for a professor
X is normally distributed with mean = = 12.6 and standard deviation = = 2.5
1)
z score for x = 15
z = 0.96
Z-score if it took the professor 15 minutes to grade = 0.96
2)
Here we have to find P(12 < X < 15)
where z is standard normal variable
= P(z < 0.96) - P(z < -0.24)
= 0.8315 - 0.4052 (From statistical table of z values)
= 0.4263
Probability that a randomly selected will require between 12 and 15 minutes to grade is 0.4263
3)
Here we have to find P(X < 15)
where z is standard normal variable
= 0.8315 (From statistical table of z values)
Probability that a randomly selected will require less than 15 minutes to grade is 0.8315