In: Math
Let X be the exam grade of a student taking Calculus 1 with Professor Smith. The professor believes that X has a mean of 81 and a standard deviation of 22. Suppose there are 100 students in Professor Smith's class.
Approximate the probability that X is higher than 83.6 OR smaller than 79.2?
Solution :
Given that,
mean = = 81
standard deviation = = 22
n = 100
= 81
= / n = 22 100= 2.2
P ( > 83.6 )
= 1 - P ( < 83.6 )
= 1 - P ( - / ) < ( 83.6 - 81/ 2.2)
= 1 - P ( z <2.6 /2.2)
= 1 - P ( z < 1.18 )
Using z table
= 1 - 0.8810
= 0.1190
P( <79.2 )
P ( - / ) < ( 79.2 - 81 / 2.2)
P ( z < -1.8 / 2.2 )
P ( z < -0.81)
= 0.1190 + 0.2090
= 0.3280
Probability = 0.3280