In: Statistics and Probability
The Title Tire and Rubber Company periodically tests its tires for tread wear under simulated road conditions. To study and control the manufacturing process, 20 samples, each containing three radial tires, were chosen from different shifts over several days of operation, with the following results. Tread wear measurements are in hundredths of an inch.
Sample | Tread Wear | ||
---|---|---|---|
1 | 31 | 42 | 28 |
2 | 26 | 18 | 35 |
3 | 25 | 30 | 34 |
4 | 17 | 25 | 21 |
5 | 38 | 29 | 35 |
6 | 41 | 42 | 36 |
7 | 21 | 17 | 29 |
8 | 32 | 26 | 28 |
9 | 41 | 34 | 33 |
10 | 29 | 17 | 30 |
11 | 26 | 31 | 40 |
12 | 23 | 19 | 25 |
13 | 17 | 24 | 32 |
14 | 43 | 35 | 17 |
15 | 18 | 25 | 29 |
16 | 30 | 42 | 31 |
17 | 28 | 36 | 32 |
18 | 40 | 29 | 31 |
19 | 18 | 29 | 28 |
20 | 22 | 34 | 26 |
Assuming that these data were collected when the manufacturing process was believed to be operating in control, develop the R chart.
Compute the upper and lower control limits for the R chart. (Round your answers to two decimal places.)
UCL= _________
LCL= _________
Assuming that these data were collected when the manufacturing process was believed to be operating in control, develop the x chart.
Compute the upper and lower control limits for the x chart. (Round your answers to two decimal places.)
UCL= _________
LCL= __________
Sample | Tread Wear | Range | Mean | ||
1 | 31 | 42 | 28 | 14 | 33.67 |
2 | 26 | 18 | 35 | 17 | 26.33 |
3 | 25 | 30 | 34 | 9 | 29.67 |
4 | 17 | 25 | 21 | 8 | 21.00 |
5 | 38 | 29 | 35 | 9 | 34.00 |
6 | 41 | 42 | 36 | 6 | 39.67 |
7 | 21 | 17 | 29 | 12 | 22.33 |
8 | 32 | 26 | 28 | 6 | 28.67 |
9 | 41 | 34 | 33 | 8 | 36.00 |
10 | 29 | 17 | 30 | 13 | 25.33 |
11 | 26 | 31 | 40 | 14 | 32.33 |
12 | 23 | 19 | 25 | 6 | 22.33 |
13 | 17 | 24 | 32 | 15 | 24.33 |
14 | 43 | 35 | 17 | 26 | 31.67 |
15 | 18 | 25 | 29 | 11 | 24.00 |
16 | 30 | 42 | 31 | 12 | 34.33 |
17 | 28 | 36 | 32 | 8 | 32.00 |
18 | 40 | 29 | 31 | 11 | 33.33 |
19 | 18 | 29 | 28 | 11 | 25.00 |
20 | 22 | 34 | 26 | 12 | 27.33 |
1.)
= 228/20 = 11.4
Here Subgroup size = 3
So, D3 = 0
D4 = 2.574
So, LCL = D3 * = 0
UCL = D4 * = 2.574 * 11.4 = 29.344
2.)
= 583.33/20 = 29.17
Here
A2 = 1.023
LCL = - A2 *
LCL = 29.17 - 1.023 * 11.4
LCL = 17.501
UCL = + A2 *
UCL = 29.17 + 1.023 * 11.4
UCL = 40.8322