Question
In: Statistics and Probability
A tire manufacturer believes that the tread life of its snow tires can be described by...
A tire manufacturer believes that the tread life of its snow tires can be described by Normal model with a mean of 32,000 miles and a standard deviation of 2500 miles.
a). If you buy a set of these tires, would it be reasonable for you to hope that they'll last 40,000 miles? Explain.
b). Approximately what fraction of these tires can be expected to last less that 30,000 miles?
c). Approximately what fraction of these tires can be expected to last between 30,000 and 35,000 miles?
d). Estimate the IQR for these data.
e). Im planning a marketing strategy, a local tire dealer wants to offer a refund to any customer whose tires fail to last a certain number of miles. However, the dealer does not want to take too big a risk. If the dealer is willing to give refunds to no more than 1 of every 25 customers, for what mileage can he guarantee these tires to last?
Solutions
orchestra answered 1 year agoRelated Solutions
A tire manufacturer believes that the life of its tires follow a normal distribution with a...
A tire manufacturer believes that the life of its tires follow a
normal distribution with a mean of 46,000 miles and a standard
deviation of 4,000 miles. What mileage can he guarantee each tire
to last so that 99% of the tires last longer than the guaranteed
lifetime?
A manufacturer claims that the average tread life of a premium tire exceeds the average tread...
A manufacturer claims that the average tread life of a premium
tire exceeds the average tread life of economy tire of the same
size by at least 5000 miles. To test this claim, 50 pieces of each
type of tires were tested under similar conditions. The premium
tire had an average tread life of 43000 miles with a sample
standard deviation of 2300, while economy tire had an average tread
life of 37500 miles with a sample standard deviation of...
the tread of life of a particular brand of tire is a random variable best described...
the tread of life of a particular brand of tire is a random
variable best described by a normal distribution with a mean of
70000 miles and a standard deviation of 9300 miles. what warranty
should the company use if they want 89.25% of the tires to outlast
the warranty? round to the nearest integer. (show work
please)
.Tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of...
.Tire manufacturer is interested in testing the fuel economy for
two different tread patterns. Tires of each tread type were driven
for 1000 miles on each of 9 different cars. The mileages, in miles
per gallon, were as follows. Test whether the mean mileage is the
same for both types of tread. (ANOVA test)
Car
1
2
3
4
5
6
7
8
9
Tread A
24.7
22.5
24.0
26.9
22.5
23.5
22.7
19.7
27.5
Tread B
20.3
19.0
22.5...
A tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires...
A tire manufacturer is interested in testing the fuel economy
for two different tread patterns. Tires of each tread type were
driven for 1000 miles on each of 9
different cars. The mileages, in miles per gallon, were as
follows:
Car
Tread A
Tread B
1
24.7
20.4
2
22.6
19.0
3
23.9
22.4
4
26.8
23.0
5
22.4
20.8
6
23.4
23.5
7
22.6
21.3
8
19.7
18.1
9
27.3
25.8
(a) Construct an 80% confidence interval for the...
A tire manufacturer claims that the life span of its tires is 52,000 miles. Assume the...
A tire manufacturer claims that the life span of its tires is
52,000 miles. Assume the life spans of the tire are normally
distributed. You selected 16 tires at random and tested them. The
mean life span of the sample is 50,802 miles. The tires had a
population standard deviation, σ = 800. Use the .05 level of
significance. a) Which distribution would be indicated? b) Explain
why you chose that distribution. c) Construct a confidence interval
for the mean...
tire manufacturer claims that the life span of its tires is 60,000 miles. Assume the life spans of the tire are normally distributed.
tire manufacturer claims that the life span of its tires is 60,000 miles. Assume the life spans of the tire are normally distributed. You selected 25 tires at random and tested them. The mean life span of the sample is 58,800 miles. The tires had a sample standard deviation, s = 600. Use the .10 level of significance.
Which distribution would be indicated?
Explain why you chose that distribution.
Construct a confidence interval for the mean using the above data....
Suppose you work at a large tire distribution center. The tires’ average tread life has been...
Suppose you work at a large tire distribution center. The tires’
average tread life has been 50,000 miles with a standard deviation
of 5,000 miles. At the end of the year, the company can reevaluate
their supply contract. There are four supply options for the next
contract: the current supplier or one of three competitors.
The current supplier produces tires with an average tread life
of 50,000 miles with a standard deviation of 5,000 miles.
Competitor A claims to produce...
The Title Tire and Rubber Company periodically tests its tires for tread wear under simulated road...
The Title Tire and Rubber Company periodically tests its tires
for tread wear under simulated road conditions. To study and
control the manufacturing process, 20 samples, each containing
three radial tires, were chosen from different shifts over several
days of operation, with the following results. Tread wear
measurements are in hundredths of an inch.
Sample
Tread Wear
1
31
42
28
2
26
18
35
3
25
30
34
4
17
25
21
5
38
29
35
6
41
42...
The Goodman Tire and Rubber Company periodically tests its tires for tread wear under simulated road...
The Goodman Tire and Rubber Company periodically tests its tires
for tread wear under simulated road conditions. To study and
control the manufacturing process, 20 samples, each containing
three radial tires, were chosen from different shifts over several
days of operation, with the following results. Tread wear
measurements are in hundredths of an inch.
Sample
Tread Wear
1
31
42
28
2
26
18
35
3
25
30
34
4
17
25
21
5
38
29
35
6
41
42...
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