Question

solve system
3x+3y-4z= 0
-x+4y+4z=6
-3x+3y+3z=3

show steps please

Answer 1

Solve for x in the second equation.

X=-6+4y+4z

Replace all occurrences of x with −6+4y+4z in each equation.

3(−6+4y+4z)+3y−4z=0

x=−6+4y+4z

−3(−6+4y+4z)+3y+3z=3

Simplify each equation.

−18+15y+8z=0

x=−6+4y+4z

18−9y−9z=3

Solve for y in the first equation.

15y=18−8z

x=−6+4y+4z

18−9y−9z=3

y=6/5−8z/15

x=−6+4y+4z

18−9y−9z=3

Replace all occurrences of y with 6/5−8z/15 in each equation.

y=6/5−8z/15

x=−6+4(6/5−8z/15)+4z

18−9(6/5−8z/15)−9z=3

Simplify each equation.

y=6/5−8z/15

x=−675+28z/15

3(12−7z)/5=3

Solve for z in the third equation.

y=6/5−8z/15

x=−6/5+28z/15

z=1

Replace all occurrences of z with 1 in each equation.

y=6/5−8(1)/15

x=−6/5+28(1)/15

z=1

Simplify

And x, y, z is

y=2/3

x=2/3

z=1

THANKS

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