Solve x^3 -3x^2 +27 = 0(mod1125)

Solve

x^3 -3x^2 +27 = 0(mod1125)

Expert Solution

Colby Messinger answered 2 years ago

Solve for x x^4 + 2x^3 + 2x^2 + 3x + 1 = 0

Solve (1+e^x)dy/dx+(e^x)y=3x^2+1 Solve (x^3+y^3)dx+3xy^2 dy = 0 Solve (y-cos y)dx + (xsiny+x)dy = 0 Solve (1+ln...

Solve (1+e^x)dy/dx+(e^x)y=3x^2+1 Solve (x^3+y^3)dx+3xy^2 dy = 0 Solve (y-cos y)dx + (xsiny+x)dy = 0 Solve (1+ln x +y/x)dx = (1-lnx)dy Solve (y^2+yx)dx - x^2dy =0 Solve (x^2+2y^2)dx = xydy Solve Bernoulli's Equation x dy/dx + 2y = (x^4)(e^x)(y^2) Solve Bernoulli's Equation (1+x^2) dy/dx = 2xy +(e^x)(y^2) Solve IVP (3e^(x^2))dy + (xy^2)dx=0 ; y(1) = 2 Solve IVP dy/dx -2xy = e^(x^2) ; y(0)=0 Solve IVP (x^2+y^2)dx+(2xy)dy=0; y(1)=1 6. Mixture Problem Initially 40 lb of salt is dissolved in a large...

use laplace transforms to solve ivp x" + 4x' + 3x = 1, x'(0) = 2,...

use laplace transforms to solve ivp x" + 4x' + 3x = 1, x'(0) = 2, x(0) = 1

solve the initial values: if Y(3)-4Y"+20Y'=51e^3x Y"(0)=41, Y'(0)= 11. Y(0)= 7 > solution is Y(x)= e^3x+2...

solve the initial values: if Y(3)-4Y"+20Y'=51e^3x Y"(0)=41, Y'(0)= 11. Y(0)= 7 > solution is Y(x)= e^3x+2 e^2x sin(4x)+6 so, what is the solution for: Y(3)-8Y"+17Y'=12e^3x Y"(0)=26, Y'(0)= 7. Y(0)= 6 Y(x)=???

use laplace transform to solve the initial value problem x'' +3x'-10x=5e^-4t; x(0)=3, x'(0)=-10

(x+3)^2/3 + (x+3)^1/3 - 6 = 0 Solve the equation.

Solve the following differential equations: 1.) y"(x)+ y(x)=4e^x ; y(0)=0, y'(0)=0 2.) x"(t)+3x'(t)+2x(t)=4t^2 ; x(0)=0, x'(0)=0

solve system 3x+3y-4z= 0 -x+4y+4z=6 -3x+3y+3z=3 show steps please

Use Laplace transforms to solve the initial value problem x′′+4x′+3x=t,x(0)=0,x′(0)=3, where primes indicate derivatives with respect...

Use Laplace transforms to solve the initial value problem x′′+4x′+3x=t,x(0)=0,x′(0)=3, where primes indicate derivatives with respect to t.

Differential Equations 22. Solve each of the following systems of equations. (c) (D-2)x=0; -3x+(D+2)y=0; -2y+(D-3)z=0 I...

Differential Equations 22. Solve each of the following systems of equations. (c) (D-2)x=0; -3x+(D+2)y=0; -2y+(D-3)z=0 I got x=c1e2t, y= 3/4 C1e2t + C2e-2t by using diffieq method d/dx(ye2t) = 3C1e2t....., but the right answer is x=4c1e2t, y= 3C1e2t + 5C2e-2t , z= -6C1e2t -2C2e-2t+C3e3t I want to know where 4 came from, and please do not use matrix system.

Question