In: Statistics and Probability
In order to estimate the number of calls to expect at a new suicide hotline, volunteers contact a random sample of 50 similar hotlines across the nation and find that the sample mean is 32.0 calls per month. Construct a 99% confidence interval for the mean number of calls per month. Assume that the population standard deviation is known to be 9.5 call per month.
(Please show all work)
Solution :
Given that,
Point estimate = sample mean = 
= 32
Population standard deviation =   
= 9.5
Sample size = n =50
At 99% confidence level the z is ,
  = 1 - 99% = 1 - 0.99 =
0.01
/ 2 = 0.01 / 2 = 0.005
Z
/2
= Z0.005 = 2.576   ( Using z table )
Margin of error = E = Z
/2*
(
/n)
= 2.576 * (9.5 / 
50)
= 3.46
At 99% confidence interval mean is,
-
E < 
 < 
 + E
32-3.46 < 
 < 32+3.46
28.54< 
 < 35.46
(28.54 , 35.46)