Question

In: Mechanical Engineering

A circular loop which possesses 55 turns is placed in a uniform magnetic field. The direction...

A circular loop which possesses 55 turns is placed in a uniform magnetic field. The direction of the magnetic field makes an angle of 70 o with respect to the normal direction to the loop. The magnetic field strength B is increased at a constant rate from B1 =3T to B2 =17T in a time interval of 20 s. If Ф1 is 3.99 Wb,

a) What is the radius of the wire? (PLEASE THOROUGHLY EXPLAIN)

b) What is the EMF?

c) What is the current if the electrical resistance of the loop is 7 ohms?

Solutions

Expert Solution

Given that,

The number of turns = N = 55

Direction of the magnetic field angle from normal =

So that the angle from the loop =

And also given

a) Now we have to find the radius of the wire for that we have the equation

Therefore the required radius of the wire = r = 0.6712 m

b)To know emf value apply the Faradays law, then we got the formula for emf as

But we know , substute this in above equation,,

We got emf is 51.2036 volts, Negative sign indecates due to application of Lenz law.

c) Given that the resistance R = 7 ohms there fore , We know the formula for current as

V = iR

i = V/R

= 51.2036/7

= 7.3148 A

Therefore our required current is 7.3148 Amps.

samet mamat answered 1 year ago

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