Question

A 20-cmcm-diameter circular loop of wire is placed in a 0.64-T magnetic field.

a) When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop?

Express your answer to two significant figures and include the appropriate units.

b) The plane of the loop is rotated until it makes a 45  angle with the field lines. What is the angle in the equation ΦB = BAcos⁡θ for this situation?

Express your answer using two significant figures.

c) What is the magnetic flux through the loop at this angle?

Answer 1

Solution:

Diameter Of Circular Loop is 20 cm

Radius of Circular Loop is 10 cm

Area Of Circular Loop is (10*10^-2)^2 = 0.01 meter^2

Magnetic Field , B = 0.64-T

A) When The plane of Loop is Perpendicular to the field Lines,

Magnetic Flux through the Loop B= (B)(A)Cos0 = 0.64*0.01=20-mWb

B) Plane of Loop is rotated until it makes a 45 angle with the field lines.

Area Vector makes 90 angle with plane of Loop, So Angle in the equation, B=BACos is = (90-45)=45 angle.

C) magnetic flux through the loop at this angle , is B = 0.64*0.01*Cos45= 14.21-mWb