A. A disk of radius 0.15 m spins at a rate of 18 rad/s. What is...

A. A disk of radius 0.15 m spins at a rate of 18 rad/s. What is the linear speed of a point on its outer rim? How long does it take that point to make a complete revolution? What would be given as the frequency in hertz of this motion?

B. A mass and spring system is built with a spring constant of 5.0 N/m and a mass of 2 kg. What is its period of oscillation? What length would a simple pendulum have to have to make an identical mass oscillate with that same period?

Solutions

Expert Solution

A) Given the radius of the disc is R = 0.15m and the angular velocity of the disc is = 18rad/s. So the linear speed on the outer rim is given by,

So the linear speed of the outer rim is 2.7m/s.

The angular displacement in one complete revolution is . So,

So the time taken by the point to make a complete revolution is 0.35s.

The frequency is given by,

So the ferquency of the motion is 2.86Hz.

B) Given the spring constant k = 5N/m and the mass hanging is m = 2kg. So the time period of oscillation is,

So the period of oscillation of spring-mass system is 3.97s.

The time period of a simple pendulum is given by,

So the length of the simple pendulum to make an identical mass oscillate with that same period is 3.91m.

genius_generous answered 1 year ago

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