In: Statistics and Probability
A health psychologist hypothesizes wants to investigate white
coat hypertension. White coat hypertension is when a patient grows
anxious when a person with a white coat and stethoscope walks into
the examination room. To investigate, the psychologist randomly
selects patients in a hospital that have come in for various minor
ailments. During this visit the doctor either wears a white coat or
a (non-white) sport coat. The patients are then asked to come in
the next week for a follow-up. At the follow-up, the doctor wears
the opposite of what he wore during the first visit. Below are the
systolic pressures of the patients at each visit. What can be
concluded with α = 0.05?
white coat | sport coat |
104 100 118 117 108 102 103 115 112 105 |
117 115 112 124 116 118 121 113 118 108 |
a) What is the appropriate test statistic?
na z-test one-sample t-test independent-samples t-test
related-samples t-test
b)
Condition 1:
health psychologist pressure minor ailments sport coat
the hospital white coat
Condition 2:
health psychologist pressure minor ailments sport coat
the hospital white coat
c) Obtain/compute the appropriate values to make a
decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
critical value = ; test statistic =
Decision: Reject H0 or Fail to reject H0
d) If appropriate, compute the CI. If not
appropriate, input "na" for both spaces below.
[ _______ , _______ ]
ANSWERS:
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Here we check the systolic pressures of the patients at each visit of a doctor with different coats i.e. white coat and sport coat.
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Ans a)
Here we use the t-test for two independent samples.
Reason: The sample size is less than 30 i.e. reason we can't use the z-test.
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Ans b)
health psychologist pressure minor ailments sport coat the hospital white coat.
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Ans c)
Null hypothesis: The Systolic blood pressure for white coat and sport coat is equal.
Alternative hypotheses: The Systolic blood pressure for white coat and sport coat is different or not equal.
Test statistic = -3.06729
Critical value = 2.119905
Decision:
Here the T-calculate = -3.07 which is less than T-critical = 2.12 which means our null hypothesis is accepted which means The Systolic blood pressure for white coat and sport coat is different or not equal.
white coat | sport coat | |
Mean | 108.4 | 116.2 |
Variance | 43.82222 | 20.84444 |
Observations | 10 | 10 |
Hypothesized Mean Difference | 0 | |
df | 16 | |
t Stat | -3.06729 | |
P(T<=t) one-tail | 0.003684 | |
t Critical one-tail | 1.745884 | |
P(T<=t) two-tail | 0.007368 | |
t Critical two-tail | 2.119905 |
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Ans d)
The 95% confidence interval is -13.19 to -2.407
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If you want manually then please comment below I will provide you an answer definitely, thank you.