In: Statistics and Probability
City1 | City 2 | City 3 | City 4 |
789 | 748 | 1831 | 1756 |
2051 | 1501 | 740 | 2125 |
765 | 1886 | 1554 | 1995 |
1645 | 1593 | 137 | 1526 |
1266 | 1474 | 2276 | 1746 |
2138 | 1913 | 2144 | 1616 |
1487 | 1218 | 1053 | 1958 |
1622 | 1006 | 1120 | 1675 |
1169 | 343 | 1838 | 1885 |
2215 | 1494 | 1735 | 2204 |
167 | 580 | 1326 | 2409 |
2557 | 1320 | 1790 | 1338 |
634 | 1784 | 32 | 2076 |
1326 | 1044 | 1455 | 2375 |
1790 | 890 | 1913 | 1125 |
32 | 1708 | 1218 | 1326 |
1455 | 1913 | 1006 | 1790 |
1218 | 343 | 32 | |
1006 | 1494 | 1455 | |
343 | 580 |
(1) Using the above table, data set has information on the account balances of customers at a bank’s four locations. Using that data set and an ? of 0.05, test the null hypothesis that the mean account balances are equal in the four towns using a one-way ANOVA in Excel?. Please provide a picture of the excel spreadsheet with the ANOVA Test results.
(2) Do you reject the null hypothesis or not? Indicate on which part of the Excel output you base your decision.
(3) Assuming that an acquaintance of yours has never heard of ANOVA, explain to him what the decision in part (b), i.e., “rejecting H0” or “not rejecting H0” means in this context at a level that can be understood by a high school senior.
1) One-way ANOVA in excel
Null and Alternative Hypothesis:
2) At =0.05, and df1=3 and df2 =72, Critical Value of Fcrit = 2.7318
And Test statistic F = 2.3527
As F < Fc, we fail to reject the null Hypothesis.
Also p-value =0.079 > =0.05, so we fail to reject the null Hypothesis.
3) Rejecting H0 means: Not all the mean account balance in four town are equal. As all mean account balance are not equal. So, we reject the null Hypothesis that they are equal in the four towns.
Not Rejecting H0 means: That we do not have enough evidence to claim that mean account balance in the four towns are not equal. So, we fail to reject that the mean account balance in the four towns is equal.