In: Statistics and Probability
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.
Solution :
Given that,
a = 0
b = 5
P(x > c) = (b - c) / (b - a)
p( x > 2.25) = ( 5 - 2.25 ) /( 5 - 0)
= 2.75/ 5
= 0.55
Probability = 0.55