In: Statistics and Probability
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 00 and 88 minutes. Find the probability that a randomly selected passenger has a waiting time greater than greater than 1.251.25 minutes.
Solution :
Given that,
a = 0
b = 8
P(x > c) = (b - c) / (b - a)
P(x > 1.25) = (8 - 1.25) / (8 - 0)
= 6.75 / 8 = 0.8438
Probability = 0.8438