find the expected count and the contribution to the chi square statistic for the (control, strongly...

find the expected count and the contribution to the chi square statistic for the (control, strongly agree) cell i. yhe two way table below

st agr. agr. neu. dis. str dis

cont 36. 48. 4. 15. 12

treat. 55. 41. 8. 4. 1

Solutions

Expert Solution

	str agr.	agr.	neu.	dis.	str dis	Totals
cont.	36=f₁₁	48=f₁₂	4=f₁₃	15=f₁₄	12=f₁₅	36+48+4+15+12=115=f₁₀
treat.	55=f₂₁	41=f₂₂	8=f₂₃	4=f₂₄	1=f₂₅	55+41+8+4+1=109=f₂₀
Totals	91=f₀₁	89=f₀₂	12=f₀₃	19=f₀₄	13=f₀₅	224=N

	str agr.	agr.	neu.	dis.	str dis.
cont.	115*91/224=46.7188	115*89/224=45.6920	115*12/224=6.1607	115*19/224=9.7545	115*13/224=6.6741
treat.	109*91/224=44.2813	109*89/224=43.3080	109*12/224=5.8393	109*19/224=9.2455	109*13/224=6.3259

	str. agr	agr.	neu.	dis.	str. dis.
cont.	(36-46.7188)^2/46.7188=2.4592	(48-45.6920)^2/45.6920=0.1166	(4-6.1607)^2/6.1607=0.7578	(15-9.7545)^2/9.7545=2.8208	(12-6.6741)^2/6.6741=4.2500
treat.	(55-44.2813)^2/44.2813=2.5946	(41-43.3080)^2/43.3080=0.1230	(8-5.8393)^2/5.8393=0.7995	(4-9.2455)^2/9.2455=2.9761	(1-6.3259)^2/6.3259=4.4840

the expected count for the (control, strongly agree) =46.7188

the contribution to the chi square statistic for the (control, strongly agree) cell=2.4592

orchestra answered 1 year ago

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