In: Statistics and Probability
Chapter 7, Section 2, Exercise 033 Find the expected count and the contribution to the chi-square statistic for the (Control, Agree) cell in the two-way table below. Strongly Agree Agree Neutral Disagree Strongly Disagree Control 36 47 6 12 11 Treatment 56 45 12 7 2 Round your answer for the excepted count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places. Expected count = contribution to the chi-square statistic =
H0: There is no relationship between Control and Agree statistics
H1: There is relationship between Control and Agree statistics
Let the los be alpha = 5%
The observed frequencies are
Strong Agree | Agree | Nautral | Disagree | Strong Disagree | Total | |
Control | 36 | 47 | 6 | 12 | 11 | 112 |
Women | 56 | 45 | 12 | 7 | 2 | 122 |
Marginal Total | 92 | 92 | 18 | 19 | 13 | 234 |
The expected frequencies are
Strong Agree | Agree | Nautral | Disagree | Strong Disagree | Total | |
Control | 44.034 | 44.034 | 8.615 | 9.094 | 6.222 | 112 |
Women | 47.966 | 47.966 | 9.385 | 9.906 | 6.778 | 122 |
Total | 92 | 92 | 18 | 19 | 13 | 234 |
The Chisquare contribution values are
Oi | Ei | (Oi-Ei)^2 /Ei |
36 | 44.034 | 1.466 |
47 | 44.034 | 0.2 |
6 | 8.615 | 0.794 |
12 | 9.094 | 0.929 |
11 | 6.222 | 3.669 |
56 | 47.966 | 1.346 |
45 | 47.966 | 0.183 |
12 | 9.385 | 0.729 |
7 | 9.906 | 0.852 |
2 | 6.778 | 3.368 |
Total: | 13.536 |
Degrees of freedom: 4
Test Statistic, X^2: 13.536
Critical X^2: 9.48772
P-Value: 0.0089
Here Chi-square value > Chi-square critical value and P-value < alpha 0.05 so we reject H0
Thus we conclude that there is relationship between Control and Agree statistics