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In: Statistics and Probability

Chapter 7, Section 2, Exercise 033 Find the expected count and the contribution to the chi-square...

Chapter 7, Section 2, Exercise 033 Find the expected count and the contribution to the chi-square statistic for the (Control, Agree) cell in the two-way table below. Strongly Agree Agree Neutral Disagree Strongly Disagree Control 36 47 6 12 11 Treatment 56 45 12 7 2 Round your answer for the excepted count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places. Expected count = contribution to the chi-square statistic =

Solutions

Expert Solution

H0: There is no relationship between Control and Agree statistics

H1: There is relationship between Control and Agree statistics

Let the los be alpha = 5%

The observed frequencies are

Strong Agree Agree Nautral Disagree Strong Disagree Total
Control 36 47 6 12 11 112
Women 56 45 12 7 2 122
Marginal Total 92 92 18 19 13 234

The expected frequencies are

Strong Agree Agree Nautral Disagree Strong Disagree Total
Control 44.034 44.034 8.615 9.094 6.222 112
Women 47.966 47.966 9.385 9.906 6.778 122
Total 92 92 18 19 13 234

The Chisquare contribution values are

Oi Ei (Oi-Ei)^2 /Ei
36 44.034 1.466
47 44.034 0.2
6 8.615 0.794
12 9.094 0.929
11 6.222 3.669
56 47.966 1.346
45 47.966 0.183
12 9.385 0.729
7 9.906 0.852
2 6.778 3.368
Total: 13.536

Degrees of freedom: 4

Test Statistic, X^2: 13.536
Critical X^2: 9.48772
P-Value: 0.0089

Here Chi-square value > Chi-square critical value and P-value < alpha 0.05 so we reject H0

Thus we conclude that there is relationship between Control and Agree statistics


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