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A gas mixture at a total pressure of 144 kPa and 327 K contains 11% H2,...

A gas mixture at a total pressure of 144 kPa and 327 K contains 11% H₂, 40% O₂, and the rest H₂O by volume. The absolute velocity of each species are −6, −3, and 12 m/s, respectively, all in the direction of the z-axis. Determine (a) the mass diffusion flux of O₂ and (b) the molar diffusion flux of O₂.

Expert Solution

Total pressure = 144kPa

Temperature = 327K

Total volume = 100 Kg moles of gas

Volume of H₂ = 11mol

Volume of O₂ = 40mol

Volume of H₂ O = 100mol - ( 11mol + 40mol) = 49mol

Molar flux for a specie X formula is

N_x = C_x V_x Where N is the molar flux, C is the molar concentration and V is the velocity

But C = moles of the gas / total volume

Molar concentration of O₂ - C = 40 / 100 = 0.4 Kg mol

Absolute velocity of O₂ = 12m/s

So Molar diffusion flux of O₂ N_o2 = 0.4 12 m/s = 4.8 mol m / s

Mass diffusion flux formula for species X is

n_x = _x V_x where n is the mass diffusion flux, is the mass concenteation and V is the velocity

But = mass of the element / volume

Mass of oxygen = 16

so for oxygen _o2 = 16 / 100 = 0.16 Kg mol

So mass diffusion flus for oxygen n_o2 = _o2 V_o2 = 0.16 12 = 1.92 Kg mol m / s

queen_honey_blossom answered 2 years ago

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