The Kc for the following reaction at 225 ∘C is 1.7×102. 3H2(g)+N2(g)⇌2NH3(g) If the equilibrium mixture...

The Kc for the following reaction at 225 ∘C is 1.7×102.

3H2(g)+N2(g)⇌2NH3(g)
If the equilibrium mixture contains 0.22 M H2 and 0.017 M N2, what is the molar concentration of NH3?

Express your answer to two significant figures and include the appropriate units.

Enter your answer using dimensions of chemical concentration.

Solutions

Expert Solution

3H2(g)+N2(g)⇌2NH3(g)

[H2] = 0.22M

[N2] = 0.017M

KC = [NH3]²/[H2]³[N2]

1.7*10² = [NH3]²/(0.22)²(0.017)

[NH3]² = 170*0.22*0.22*0.017

[NH3]² = 0.139876

[NH3] = 0.37

queen_honey_blossom answered 1 year ago

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