The Kc for the following reaction at 225 ∘C is 1.7×102. 3H2(g)+N2(g)⇌2NH3(g) If the equilibrium mixture...

The Kc for the following reaction at 225 ∘C is 1.7×102.

3H2(g)+N2(g)⇌2NH3(g)
If the equilibrium mixture contains 0.22 M H2 and 0.017 M N2, what is the molar concentration of NH3?

Express your answer to two significant figures and include the appropriate units.

Enter your answer using dimensions of chemical concentration.

Expert Solution

3H2(g)+N2(g)⇌2NH3(g)

[H2] = 0.22M

[N2] = 0.017M

KC = [NH3]²/[H2]³[N2]

1.7*10² = [NH3]²/(0.22)²(0.017)

[NH3]² = 170*0.22*0.22*0.017

[NH3]² = 0.139876

[NH3] = 0.37

queen_honey_blossom answered 1 year ago

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