In: Economics
Multiple Regression Analysis
The company has been able to determine that its sales in dollars depend on advertising and
of the number of sellers and for this reason, it uses the data from previous years to
be able to forecast possible sales for the year 2020.
Y X1 ($ 000) X2 ($ 000)
Year Sales Advertising Salesman
2013 $ 10 $ 1 1
2014 $ 15 $ 2 1
2015 $ 25 $ 3 2
2016 $ 40 $ 5 3
2017 $ 70 $6 3
2018 $ 110 $ 8 4
2019 $ 150 $ 9 6
INSTRUCTIONS:
a) Calculate the values of the letters a, b1, b2. (excel)
b) Write down the problem Regression equation
c) Calculate sales by 2020 if the advertising were $ 14,000 and the number of sellers out of 10.
We have the following data from the given problem.
Year | Sales | Advertising | Salesman |
2013 | 10 | 1 | 1 |
2014 | 15 | 2 | 1 |
2015 | 25 | 3 | 2 |
2016 | 40 | 5 | 3 |
2017 | 70 | 6 | 3 |
2018 | 110 | 8 | 4 |
2019 | 150 | 9 | 6 |
a) Now, the regression equation is Y = a +b1x1+ b2x2 +u
here, Y = sales
x1 = Advertisement
x2 = Salesman
Using excel we get the following result.
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.97 | |||||||
R Square | 0.95 | |||||||
Adjusted R Square | 0.92 | |||||||
Standard Error | 14.55 | |||||||
Observations | 7.00 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 2.00 | 16003.65 | 8001.82 | 37.82 | 0.00 | |||
Residual | 4.00 | 846.35 | 211.59 | |||||
Total | 6.00 | 16850.00 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | -23.96 | 11.11 | -2.16 | 0.10 | -54.80 | 6.89 | -54.80 | 6.89 |
Advertising (A) | 7.60 | 6.96 | 1.09 | 0.34 | -11.73 | 26.94 | -11.73 | 26.94 |
Salesmane (Sa) | 16.46 | 11.88 | 1.39 | 0.24 | -16.52 | 49.43 | -16.52 | 49.43 |
Thus, a = -23.96
b1 = 7.60
b2 = 16.46
b) The regression equation is - Y = -23.96 + 7.60x1 + 16.46x2
c) In 2020, x1 = 14 and x2 = 10
Putting this in the above equation we get,
Y = -23.96 + 7.60 * 14 + 16.46 * 10 = 247
Thus, sales in 2020 = 247000