Question

In: Chemistry

If the surface area of the Pacific Ocean is 1.6176 x 10^8 km^2 and the average...

If the surface area of the Pacific Ocean is 1.6176 x 10^8 km^2 and the average depth is 4,080 meters, how many moles of water in the Pacific?

Solutions

Expert Solution

Surface qrea of the pacific ocean = 1.6176*108km2  

                                       Km          = 1000m

                                        = 1.6176*108 *(1000m)2

                                         = 1.6176*1014 m2

              depth                 = 4080 m

volume                            = area * depth

                                           = 1.6176*1014 * 4080

                                             = 6.599*1017 m3

                                             = 6.61017 L     = 6.6*1020 ml

mass of water                      = volume * density of water              [density of water = 1g/ml]

                                           = 6.6*1020 *1

                                            = 6.6*1020

no of moles of H2O              = W/G.M.Wt

                                              = 6.6*1020/18

                                               = 3.6*1019 moles


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