Find the area enclosed by the curves, x + y = 8 and x = y^2...
Find the area enclosed by the curves, x + y = 8 and x = y^2 − 4y
+ 4.
Solutions
Expert Solution
First we find the intersection points of line and given
parabola. Considering horizontal strip, we obtained the area
between line and parabola by integration. The area is 125/6
sq.unit.
1. Find the area between the curves y = x2 and y = x
+ 2.
Round your answer to one decimal place.
2. Find the area under the curve defined by the following data
points:
x
1
4
7
10
13
16
19
22
25
y
4.2
4.6
4.8
6.2
6.8
7.8
9.1
8.8
9.4
Round your answer to 2 decimal places.
I appreciate your help :)
FIND THE CENTROID:
a. of the region enclosed between the curves y=x1/2 ,
y=1, y=2 and the y-axis.
b. of the 1st quadrant area bounded by the curve
y=4-x2
c. of the region bounded by the curve y=x3 and
x=y2
Consider the region R enclosed between the curves y = 2 /x and y
= 1, between x = 1 and x = 2.
Calculate the volume of the solid obtained by revolving R about
the x-axis,
(a) using cylindrical shells;
(b) using washers
Sketch the region enclosed by the given curves.
y = 8 cos
8x, y = 8 − 8 cos
8x, 0 ≤ x ≤
π/6
I already have the sketch however I need its Area
A) Find its area