We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adn reacting with 0.75g KOH and 5 mL triethylene...

We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adn reacting with 0.75g KOH and 5 mL triethylene glycol to produce diphenyl acetylene.

What is the theoretical yield?

Solutions

Expert Solution

(C₆H₅)₂ C₂H₂Br₂ + KOH ----------------> (C₆H₅)₂ C₂

general 340g 178.22g

Given 0.75g 0.75g 0

Here triethylene glycol is a solvent and KOH is excess reagent

340g 1,2-dibromo-1,2-diphenylethane can from 178.22g diphenyl acetylene.

0.75g 1,2-dibromo-1,2-diphenylethane can from 178.22*0.75/340=0.3931g diphenyl acetylene.

queen_honey_blossom answered 1 year ago

Next > < Previous

Related Solutions

After reacting 1.45 g of salicylic acid with 5.0 mL of acetic anhydride, 1.75 g of...

After reacting 1.45 g of salicylic acid with 5.0 mL of acetic anhydride, 1.75 g of acetylsalicylic acid is obtained. What is the calculated percent yield? Provide your answer to the correct number of significant figures.

A solution is made by dissolving 40.0 g of KOH in 100 mL of water (density...

A solution is made by dissolving 40.0 g of KOH in 100 mL of water (density 0.995 g/mL) to form a solution. What is the mass percent solute in the solution? 1. 40.2% 2. 40.0% 3. 3.49% 4. 28.6% 5. 28.7%

If Compound A (256 mg) was hydrolyzed using 12.5 mL of 1.0 M KOH and the...

If Compound A (256 mg) was hydrolyzed using 12.5 mL of 1.0 M KOH and the amount of remaining KOH was back titrated and required 44.9 mL of 0.25 M HCL to neutralize the excess NaOH, what were the saponification equivalent and neutralization equivalent, and what is compound A?

a)Using a 0.15 M Acetate buffer with a pH of 4.9, you add 0.75 mL of...

a)Using a 0.15 M Acetate buffer with a pH of 4.9, you add 0.75 mL of 0.08 M HCl to 73 mL of the buffer. What is the new pH of the solution? (Enter your answer to three significant figures.) b) Using a 0.15 M Acetate buffer with a pH of 4.9, you add 0.75 mL of 0.08 M NaOH to 73 mL of the buffer. What is the new pH of the solution? (Enter your answer to three significant...

Using a 0.25 M phosphate buffer with a pH of 7.6, you add 0.75 mL of...

Using a 0.25 M phosphate buffer with a pH of 7.6, you add 0.75 mL of 0.45 M NaOH to 59 mL of the buffer. What is the new pH of the solution?

Convert the following equivalents to masses/volumes (g or mL): 1. 1.5 equivalents of KOH 2. 1.4...

Convert the following equivalents to masses/volumes (g or mL): 1. 1.5 equivalents of KOH 2. 1.4 equivalents of RCO3H 3. 1.2 equivalents of NaOH 4. 0.2 equivalents of NaOH 5. 3.5 equivalents of ethyl bromide

3.00 g of potassium hydroxide (KOH) pellets are put into a constant-pressure calorimeter containing 250 mL...

3.00 g of potassium hydroxide (KOH) pellets are put into a constant-pressure calorimeter containing 250 mL of water. The initial temperature of the water is 22.3°C. The mixture is then stirred until all of the KOH is dissolved. The final temperature of the solution is measured and recorded as 29.7°C. Calculate the heat of solution for potassium hydroxide (ΔHsoln). The specific heat capacity of the solution may be assumed to be the same as that of water since this is...

The recommended dose of quinine is 0.800 g/kg. If we assume the density is 1 g/ml...

The recommended dose of quinine is 0.800 g/kg. If we assume the density is 1 g/ml what is the ph of this solution? the molar mass of quinine is 324.412. If 100 ml of this solution is titrated with a solution of 0.010 M HCL how many ml of HCL are required to reach the first equivalence point? what is the ph there? What is the PH when 32 ML of HCL have been added? what is the ph at...

Lab: Hydrolysis of polyethylene terephthalate using KOH 1. Why do we need to keep this reaction...

Lab: Hydrolysis of polyethylene terephthalate using KOH 1. Why do we need to keep this reaction well stirred? 2. what is the scope of this reaction? 3. IR and NMR interpretation of dimethyl terephthalate 4. What is the role of 1-pentanol and water in this experiment? 5. Explain Alkaline hydrolysis of PET using KOH (in words).

A recrystallization of 3.00 g of benzoic acid is to be performed using 80 ml of...

A recrystallization of 3.00 g of benzoic acid is to be performed using 80 ml of water. The solubility of benzoic acid in water is 0.680 g/10.0 ml at 100oC and 0.0290 g/10.0 ml at room temperature. 3a) What is the minimum volume of boiling water needed to dissolve the 3.00 g of benzoic acid? 3b) How much of the benzoic acid (in grams) will theoretically recrystallize after heating to boiling and then cooling to room...

Subjects