We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adn reacting with 0.75g KOH and 5 mL triethylene...

We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adn reacting with 0.75g KOH and 5 mL triethylene glycol to produce diphenyl acetylene.

What is the theoretical yield?

Expert Solution

(C₆H₅)₂ C₂H₂Br₂ + KOH ----------------> (C₆H₅)₂ C₂

general 340g 178.22g

Given 0.75g 0.75g 0

Here triethylene glycol is a solvent and KOH is excess reagent

340g 1,2-dibromo-1,2-diphenylethane can from 178.22g diphenyl acetylene.

0.75g 1,2-dibromo-1,2-diphenylethane can from 178.22*0.75/340=0.3931g diphenyl acetylene.

queen_honey_blossom answered 1 year ago

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