In: Statistics and Probability
In the survey on the quality of coffee A carried out among 90 randomly selected customers of the company dealing with its distribution, the following ratings were obtained:
| Rating | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 
| Number of people | 2 | 4 | 4 | 10 | 17 | 18 | 21 | 8 | 6 | 
a) Based on the above data, the hypothesis was verified that 40% of all customers put coffee higher than '6' with the alternative that less than 40% giving such a rating. So the p-value of the relevant test is:
b) The p-value calculated in the previous section will be LOWER /
SAME / HIGHER than the p-value calculated for the alternative
assuming that the percentage is different from 40%
a)
Ho :   p ≥ 0.4  
H1 :   p <   0.4   (Left tail
test)
          
Level of Significance,   α =   
0.05  
Number of Items of Interest,   x = 21+8+6 =
35  
Sample Size,   n =    90  
          
Sample Proportion ,    p̂ = x/n =   
0.3889  
          
Standard Error ,    SE = √( p(1-p)/n ) =   
0.05164  
Z Test Statistic = ( p̂-p)/SE =   
(0.3889-0.4)/0.0516=   -0.2152  
          
p-Value   =  
0.4148   [excel function
=NORMSDIST(z)]
2)
The p-value calculated in the previous section will be LOWER than the p-value calculated for the alternative assuming that the percentage is different from 40%