Question

In: Statistics and Probability

In the survey on the quality of coffee A carried out among 90 randomly selected customers...

In the survey on the quality of coffee A carried out among 90 randomly selected customers of the company dealing with its distribution, the following ratings were obtained:

Rating 1 2 3 4 5 6 7 8 9
Number of people 2 4 4 10 17 18 21 8 6

a) Based on the above data, the hypothesis was verified that 40% of all customers put coffee higher than '6' with the alternative that less than 40% giving such a rating. So the p-value of the relevant test is:


b) The p-value calculated in the previous section will be LOWER / SAME / HIGHER than the p-value calculated for the alternative assuming that the percentage is different from 40%

Solutions

Expert Solution

a)

Ho :   p ≥ 0.4  
H1 :   p <   0.4   (Left tail test)
          
Level of Significance,   α =    0.05  
Number of Items of Interest,   x = 21+8+6 = 35  
Sample Size,   n =    90  
          
Sample Proportion ,    p̂ = x/n =    0.3889  
          
Standard Error ,    SE = √( p(1-p)/n ) =    0.05164  
Z Test Statistic = ( p̂-p)/SE =    (0.3889-0.4)/0.0516=   -0.2152  
          

p-Value   =   0.4148   [excel function =NORMSDIST(z)]

2)

The p-value calculated in the previous section will be LOWER than the p-value calculated for the alternative assuming that the percentage is different from 40%


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