In: Statistics and Probability
A survey of 25 randomly selected customers found the ages shown (in years).
The mean is 32.64 years and the standard deviation is 9.97 years.
a) What is the standard error of the mean?
b) How would the standard error change if the sample size had been
400
instead of
25?
(Assume that the sample standard deviation didn't change.)
Solution :
Given that ,
mean = = 32.64
standard deviation = = 9.97
n = 25
standard error = = / n =9.97 / 25=1.994
= 1.994
(B)
n = 400
standard error = = / n =9.97 / 400=0.4985
= 0.4985