In a survey, among 350 randomly selected single women, 77 of them said that they "definitely...

In a survey, among 350 randomly selected single women, 77 of them said that they "definitely want to get married." In the same survey, among 400 randomly selected single men, 112 of them gave that same response. Assume that these samples are independent. Use a 0.01 signifficant level and the P-value method to test the claim that the proportion of single women who definitely want to get married is less than the one of single men who definitely want to get married. What is the P-value?

Select one:

a. 2.95%

b. None of the other answers is true.

c. 5.90%

d. 1.48%

e. 0.74%

Expert Solution

orchestra answered 2 years ago

In a survey, 24% of 230 single women said that they "definitely want to get married."...

In a survey, 24% of 230 single women said that they "definitely want to get married." In the same survey, 22% of 270 single men gave the response. Construct a 99% confidence interval estimate of the difference between the proportions of single women and single men who definitely want to get married. Is there a gender gap? 1. Construct a 95% confidence interval estimate. ___ < p1 - p2 < ___ (Round to three decimal places as needed) 2. Is...

12 Among 500 randomly selected adults were surveyed, there are 25% of them said that they...

12 Among 500 randomly selected adults were surveyed, there are 25% of them said that they used the Internet for shopping at least a few times a year. Construct a 90% confidence interval estimate of the percentage of adults who use the Internet for shopping. Select one: a. (20.0%, 30.0%) b. (26.0%, 34.0%) c. (21.8%, 28.2%) d. (24.7%, 31.3%) e. None of the other answers is true. 14 To study the effects of prenatal cocaine use on infants, on collects...

Among 500 randomly selected adults were surveyed, there are 25% of them said that they used...

Among 500 randomly selected adults were surveyed, there are 25% of them said that they used the Internet for shopping at least a few times a year. Construct a 99% confidence interval estimate of the percentage of adults who use the Internet for shopping.

In a recent survey of 60 randomly selected college students, 43 said that they believe in...

In a recent survey of 60 randomly selected college students, 43 said that they believe in the existence of extraterrestrial life. a) Find p?, the sample proportion that believes that there is extraterrestrial life. (Round your answers to three decimal places). p? = b)The 99 % margin of error associated with this estimate is: c) The 99 % confidence interval for the true proportion of all college students who believe there is extraterrestrial life is: to d) A recent report...

Of 150 patients randomly selected by a hospital, 90 of them said that their health insurance...

Of 150 patients randomly selected by a hospital, 90 of them said that their health insurance was not adequate. (a) Construct a 99% confidence interval for the proportion of patients who would say that their health insurance was not adequate. (b) Can we say that more than 50% of all patients of the hospital did not have adequate health insurance? Test at the 1% significance level.

In a survey of 356 randomly selected gun owners, it was found that 82 of them...

In a survey of 356 randomly selected gun owners, it was found that 82 of them said they owned a gun primarily for protection. Find the margin of error and 95% confidence interval for the percentage of all gun owners who would say that they own a gun primarily for protection. Round all answers to 3 decimal places. Margin of Error (as a percentage): % Confidence Interval: % to %

In the survey on the quality of coffee A carried out among 90 randomly selected customers...

In the survey on the quality of coffee A carried out among 90 randomly selected customers of the company dealing with its distribution, the following ratings were obtained: Rating 1 2 3 4 5 6 7 8 9 Number of people 2 4 4 10 17 18 21 8 6 a) Based on the above data, the hypothesis was verified that 40% of all customers put coffee higher than '6' with the alternative that less than 40% giving such a...

In a recent survey of 910 randomly selected likely voters in Indiana, 477 said they oppose...

In a recent survey of 910 randomly selected likely voters in Indiana, 477 said they oppose a proposal to tax internet sales. Based on this sample, can we say at the 5% alpha level that at least 50% of the voters in Indiana oppose the tax? Answer this question by using the normal approximation to the binomial to conduct the appropriate 1-sided test (that is, write the hypotheses and find the test statistic) by hand. (Remember, by-hand work does not...

In a survey of 170 randomly selected Ohioans, sixteen said that they were left-handed. a. Calculate...

In a survey of 170 randomly selected Ohioans, sixteen said that they were left-handed. a. Calculate the percentage of the people surveyed who were left-handed, rounded to the nearest hundredth of a percent. b. Estimate the margin of error, assuming a 95% confidence level. Round to the nearest hundredth of a percent. c. Determine a 95% confidence interval for the relevant population percentage. d. Write a confidence statement corresponding to your answer in part c. e. An observer could look...

In a recent survey of 4276 randomly selected households showed that 3549 of them had telephones....

In a recent survey of 4276 randomly selected households showed that 3549 of them had telephones. Using these results, construct a 99% confidence interval estimate of the true proportion of households with telephones. Use the PANIC acronym

Question