In: Civil Engineering
A cylindrical soil sample, 7.3 cm in diameter and 16.8 cm in height, is tested in a constant-head permeability apparatus. A constant head of 75 cm is maintained during the test. After 1 minute of testing, a total of 945.7 gm of water was collected. The temperature was 20 oC. The void ratio of the soil was 0.43. Calculate the following:
The hydraulic gradient
The flow rate
The discharge velocity
The seepage force per unit volume
The coefficient of permeability
GIVEN;
Diameter of sample, D=7.3 cm
Height/Length of sample, L=16.8 cm =0.168 m
Weight of water collected in 1 minute, W= 945.7gm =0.9457 kg
Constant head, H= 75 cm 0.75 m
Time, t= 1 Minute = 60 sec
Void ratio, e=0.43
Solution:
Cross sectional area of sample, A= (D2)/4
A=( x7.3x7.3)/4
A= 41.85 cm2
A= 0.004185 m2
Volume of water collected in time t, Q= (Weight of water)/(Density of water)
Q= 0.9457/1000 m3
Q=0.0009457 m3
(i) Hydraulic gradient, i=H/L
i= 75/16.8
i=4.464
(ii) The flow rate , q= kiA
k= (QL)/(tHA)
i=H/L
q=(QL/tHA)x(H/L)xA
q=Q/t
q=0.0009457/60
q= 1.58x10-5 m3/s
(iii) Discharge velocity, V= ki = q/A
V= (1.58x10-5)/ (0.004185)
V= 3.78x10-3 m/s
(iv) Seepage force per unit volume Fs= iw
Fs= (Hw)/L
Fs= (0.75x9.81)/0.168
Fs= 43.79 KN
(v) The coefficient of permeability , k= (QL)/(tHA)
k= V/i
k= (3.78x10-3)/4.464
k=8.14x10-4 m/s