Question

In: Statistics and Probability

The patient recovery time from a particular procedure is normally distributed with a mean of 5.2...

The patient recovery time from a particular procedure is normally distributed with a mean of 5.2 days and a standard deviation of 1.8 days.

what is the probability of spending more than 2 days in recovery? (round your answer to four decimal places)

Solutions

Expert Solution

ANSWER:

Given that,

The patient recovery time from a particular procedure is normally distributed with a mean of 5.2 days and a standard deviation of 1.8 days.

Mean = = 5.2

Standard deviation = = 1.8

We know that,

z = (x-) / = (x-5.2) / 1.8

what is the probability of spending more than 2 days in recovery? (round your answer to four decimal places)

P(x > 2) = P((x-) / > (x-5.2) / 1.8)

P(x > 2) = P(z > (2-5.2) / 1.8)

P(x > 2) = P(z > -3.2 / 1.8)

P(x > 2) = P(z > -1.78)

P(x > 2) = 1 - P(z < -1.78)

P(x > 2) = 1 - 0.03754 (From z score table as given below)

P(x > 2) = 0.96246

P(x > 2) = 0.9625 (Rounded to four decimal places.)

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