In: Statistics and Probability
The given word is STAIR.
Question (a)
We have to find how many 5 letter combinations can be made from the word STAIR.
Now, in the word, there are 5 distinct letters.
These 5 letters can be arranged among themselves in 5 places of the word, in 5! number of ways.
5!=5*4*3*2*1=120
From the word STAIR, 120 five-letter combinations can be made.
Question (b)
Now, the vowels cannot be side by side.
There are two vowels in the word, namely A and I.
Now, first let us find the number of ways in which these 2 vowels stay side by side.
Now, if we consider the two vowels as a single entity, there are 4 distinct entities; S,T,R and AI.
These 4 can permutate among themselves in 4! number of ways.
The two vowels can permutate amog themselves in 2 ways.
So, the total number of 5-letter combinations in which the vowels are together, is
4!*2, ie. 48.
Now, total number of 5-letter words is 120.
Total number of 5-letter words, in which the vowels are together, is 48.
So, the number of words in which the vowels are not together, is 120-48, ie. 72.
The answer is 72.