In: Accounting
Lakeside, Inc., is considering replacing old production equipment with state-of-the-art technology that will allow production cost savings of $10,000 per month. The new equipment will have a five-year life and cost $390,000, with an estimated salvage value of $40,000. Lakeside’s cost of capital is 10%. Required: Calculate the payback period and the accounting rate of return for the new production equipment. (Round your answers to 2 decimal places.)
Ans. 1 | Payback period = Initial investment / Annual cash inflows | |||
$390,000 / $120,000 | ||||
3.25 | years | |||
*Annual cash inflows = Cost savings per month * Number of months in a year | ||||
$10,000 * 12 | ||||
$120,000 | ||||
Ans. 2 | Accounting rate of return = (Annual cash inflow - Depreciation) / Average investment * 100 | |||
($120,000 - $70,000) / $215,000 * 100 | ||||
$50,000 / $215,000 * 100 | ||||
23.26% | ||||
*Depreciation = (Cost of machine - Salvage value) / Useful life | ||||
($390,000 - $40,000) / 5 | ||||
$350,000 / 5 | ||||
$70,000 | ||||
*Average investment = (Cost of asset + Salvage value) / 2 | ||||
($390,000 + $40,000) / 2 | ||||
$430,000 / 2 | ||||
$215,000 | ||||
Ans. | *Calculations for Present value of cash inflows: | |||||
Year | PV @10% calculations | PV @ 10% | Cash inflows | Present value of cash inflow | ||
1 | 1 / (1 + 0.10)^1 = | 0.9091 | $120,000 | $109,092.00 | ||
2 | 1 / (1 + 0.10)^2 = | 0.8264 | $120,000 | $99,168.00 | ||
3 | 1 / (1 + 0.10)^3 = | 0.7513 | $120,000 | $90,156.00 | ||
4 | 1 / (1 + 0.10)^4 = | 0.6830 | $120,000 | $81,960.00 | ||
5 | 1 / (1 + 0.10)^5 = | 0.6209 | $120,000 | $74,508.00 | ||
5 | 1 / (1 + 0.10)^5 = | 0.6209 | $40,000 | $24,836.00 | ||
Total Present Value of Cash Inflows | $479,720.00 | |||||
Total Present Value of Cash Inflows | $479,720.00 | |||||
Less: Cost of equipment | -$390,000 | |||||
Net present value | $89,720.00 | |||||