What does it mean for a free energy diagram of an equilibrium reaction when delta G...

What does it mean for a free energy diagram of an equilibrium reaction when delta G is zero? Does that mean that the entire diagram would just be a horizontal line, or would there still be transition and intermediate states?

Solutions

Expert Solution

It is a very nice question first of all...now lets discuss this,

The answer lies in the definition of equilibrium...which is..at equilibrium RATE of formation of products is EQUAL to RATE of formation of reactant.
Now this means reaction has not stopped.. it just seems like stop..but bond from product side is breaking to form reactant and same thing is happening from reactant side...which obviously require energy otherwise it will be violation of "law of conservation of energy" which says energy can neither be created nor be destroyed...so this proves that the diagram is definitely not a straight line but a small plateau...which can easily be crossed by both the sides(reactant and product)...
Now if there is a plateau so there is definitely a trasition state which involves the breaking and forming of bonds (which obviously cant be isolated)..but not intermediate state because that will change the profile of reaction coordinate of equilibrium.

Hope you got the answer please give feedback

queen_honey_blossom answered 1 year ago

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