What is the pH of a solution that results when 0.012 mol HNO3 is added to 610.0 mL of a solution that is 0.26 M in aqueous ammonia and 0.46M in ammonium nitrate. Assume no volume change. (Kb for NH3 = 1.8 × 10–5.)
a. 8.96
b. 9.56
c. 5.04
d. 9.01
e. 4.44
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When a cell reaction reaches equilibrium, E = 0. E = 0. both E and E = 0. neither E nor E = 0.
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Calculate analytical concentration for each of the following solutions:
a) HCl solution, pH = 1.34
b) Acetic acid solution, pH = 4.31
c) Sulfuric acid solution, pH = 2.21
d) Potassium hydroxide solution, pH = 12.21
Acetic acid: pKa = 4.76
Sulfuric acid: pKa,1 = strong, pKa,2 = 1.99
In water, [H3O+][OH–] = 1.00 ! 10–14
Ignore the effect of ionic strength.
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g. Which of the above compounds are ionic? Which are molecular?
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Calculate [H3O+] and [OH−] for each of the follo...
pH= 8.56
pH= 11.20
pH= 2.84
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A.
Calculate [H3O+] in the following aqueous solution at 25 ?C: [OH?]= 1.6×10?9 M .
Express your answer using two significant figures.
B.
Calculate [H3O+] in the following aqueous solution at 25 ?C: [OH?]= 3.0×10?2 M .
Express your answer using two significant figures.
C.
Calculate [H3O+] in the following aqueous solution at 25 ?C: [OH?]= 7.0×10?12 M .
Express your answer using two significant figures.
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4. A puddle of coastal seawater, caught in a depression formed by some coastal rocks at high tide, begins to evaporate as the tide goes out. If the volume of a puddle decreases to 23% of its original volume, what is the sodium chloride concentration if it was initially 0.449 M?
5. Iron (II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe (II) to Fe (III):
4 Fe(OH)+ (aq) + 4 OH- (aq) + O2(aq) + 2H2O (L) ? 4 Fe(OH)3 (s)
How many grams of oxygen are needed to precipitate all of the iron in 75 mL of 0.090 M Fe(II)?
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Calculate the activity at 25 degrees Celsius of NACl(s) at 1, 10, 100, and 1000 bar. The density of NaCl at 25 degrees Celsius and 1 bar is 2.16 (g/cm3).
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If the Ksp of PbI2 is 7.1 x 10-9 will precipitation occur when 10 mL of 1.0 x 10-4 Pb(NO3)2 is mixed with 10 mL of 1.0 x 10^-3 M KI? (Show calculation)
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Fresh orange juice containing 10 % solids and the balance water is fed to an evaporator to produce final product of concentrated orange juice containing 40% solids. A fraction of the fresh juice bypassed the evaporator to insure fresh taste. The juice that enters the evaporator at 10% is concentrated and leaves the evaporator at 60% solids, and the evaporator product stream is then mixed with the bypassed fresh juice to achieve the desired final concentration of 40 % solids. All percentages are in mass%. Draw and label a flowchart of this process and based on 100 lb/hr of the final 40% mass product. calculate the following flow rates in Lb/hr:
a. Fresh overall feed rate to the process
b. Flow rate of pure water leaving the evaporator and the bypass flow rate
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Balance each of the following redox reactions occurring in basic solution.
Express your answer as a chemical equation. Identify all of the phases in your answer.
H2O2(aq)+ClO2(aq)?ClO?2(aq)+O2(g)
Al(s)+MnO?4(aq)?MnO2(s)+Al(OH)?4(aq)
Cl2(g)?Cl?(aq)+ClO?(aq)
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In a reaction, aqueous NaOH is titrated against sulfuric acid solution, H2SO4, according to the equation:
2 NaOH (aq) + H2SO4 (aq) --> Na2SO4 (aq) + 2H2O (l)
If 18.62 ml of sulfuric acid are neutralized with 25.00 mL of 0.100 M NaOH, what is its molar concentration (Molarity, M) of sulfuric acid solution?
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Hey guys,
So I am doing a presentation on the element Gold, Au. Now I could go look up the information online but I am really running out of time here, could someone provide me with as much information as you can on the elemnt gold(NOTE NOT PLAGIARIZED). Please cite everything and just hook me up with as many paragraphs and information on gold as you can. I will downrate you if you just do a lazy copy paste from google so please be cautius. If this is too much then just ignore this question. BTW even if you can't write paragraphs about gold, try to atleast give me some ideas and questions about the element so that I can answer and finish this powerpoint. THANK YOU!
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Explain why the mutation of Asp-52 to Asn-52 decreases enzyme activity of lysozymes by 10,000 fold.
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Solution | Absorbance | [Fe(SCN)2+]eq |
B-1 | 0.060 | 1.4*10-5 |
B-2 | 0.151 | 3.8*10-5 |
B-3 | 0.323 | 8.07*10-5 |
B-4 | 0.381 | 9.5*10-5 |
B-5 | 0.427 | 1.06*10-4 |
Solution | Vol of 0.002 M Fe3+ | Volume of 0.002 M SCN- | Volume of H2O | |
B-1 | 5.0 mL | 1.0 mL | 5.0 mL | |
B-2 |
|
2.0 mL | 4.0 mL | |
B-3 | 5.0 mL | 3.0 mL | 3.0 mL | |
B-4 | 5.0 mL | 4.0 mL | 2.0 mL | |
B-5 | 5.0 mL | 5.0 mL | 1.0 mL |
2. Determine the equilibium concentration of each of the reactants and products in Solution B-1 using the table provided below (ICE table). Fill in all blank values
[Fe3+] | [SCN-] | [Fe(SCN)2+] | |
Initial Concentration | |||
Change in Equilibrium | |||
Equilibrium Concentration |
3.Determine the equilibium concentration of each of the reactants and products in Solution B-2 using the table provided below (ICE table). Fill in all blank values
[Fe3+] | [SCN-] | [Fe(SCN)2+] | |
Initial Concentration | |||
Change in Concentration | |||
Equilibrium Concentration |
4.Determine the equilibium concentration of each of the reactants and products in Solution B-3 using the table provided below (ICE table). Fill in all blank values
[Fe3+] | [SCN-] | [Fe(SCN)2+] | |
Initial Concentration | |||
Change in Concentration | |||
Equilibrium Concentration |
5. Determine the equilibium concentration of each of the reactants and products in Solution B-4 using the table provided below (ICE table). Fill in all blank values
[Fe3+] | [SCN-] | [Fe(SCN)2+] | |
Initial Concentration | |||
Change in Equilibrium | |||
Equilibrium Concentration |
6.Determine the equilibium concentration of each of the reactants and products in Solution B-5 using the table provided below (ICE table). Fill in all blank values
[Fe3+] | [SCN-] | [Fe(SCN)2+ | |
Initial Concentration | |||
Change in Equilibrium | |||
Equilibrium Concentration |
I have no idea how to do problems 2-6. Could someone please help me. Your help is always greatly appreciated! Thank you in advance.
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