In: Chemistry
A certain weak acid, HA, has a Ka value of 7.3
Part A
HA -------------------------------------> H+ + A-
0.1 0 0 initially
0.1 (1- y) 0.1 y 0.1 y
Ka = 0.1 y2 because for weak acid y <<<<<1
Ka = 7.3 x 10-7 so y = 2.7 x 10-3
Percentage of ionization is 0.27
Case B
y = 8.54 x 10 -3
Percentage of ionization is 0.85