Questions
1.) Acetic acid is a weak monoprotic acid with Ka=1.8*10^-5. In an acid base titration, 100...

1.) Acetic acid is a weak monoprotic acid with Ka=1.8*10^-5. In an acid base titration, 100 mL of 0.100M acetic acid is titrated with 0.100M NaOH. What is the pH of the solution:

a.)Before any NaOH is added

b.)Before addition of 15.0mL of 0.100M NaOH

c.)At the half-equivalence point

d.)After addition of total of 65.0mL of 0.100M NaOH

e.)At equivalence point

f.)After addition of a total of 125.0mL of 0.100M NaOH

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The half-equivalence point and the equivalence point should not be noted when measuring pH changes during...

The half-equivalence point and the equivalence point should not be noted when measuring pH changes during a titration. True or False ?

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How many grams of each of the following per 1000g of water in your car radiator...

How many grams of each of the following per 1000g of water in your car radiator are needed to give equal protection against freezing down to -10.0°C? (a) Methyl alcohol (CH3OH) b.p is 65°C, (b) ethyl alcohol (C2H5OH) b.p is 78°C, (c) ethylene glycol (C2H4(OH)2) b.p is 197°C. In spite of higher cost, what advantages does ethylene glycol have over the other alcohols as an all-winter antifreeze?

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Which one of the following will act as a buffer solution? A. 25 ml of 0.1...

Which one of the following will act as a buffer solution?

  • A.

    25 ml of 0.1 M NH4Cl solution mixed with 12.5 mL of 0.1 M NaCl solution

  • B.

    25 mL of 0.1 M NH4Cl solution mixed with 25 mL of 0.1 M NaOH solution

  • C.

    25 mL of 0.1 M HCl solution mixed with 12.5 mL of 0.1 M NaCl solution

  • D.

    12.5 mL of 0.1 M acetic acid solution mixed with 25 mL of 0.1 M NaOH solution

  • E.

    25 mL of 0.1 M acetic acid solution mixed with 12.5 mL of 0.1 M NaOH solution

clear solution would be greatly appreciated :)!

will rate, thank you!

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The Winkler method for dissolved oxygen in water is based on the rapid oxidation of solid...

The Winkler method for dissolved oxygen in water is based on the rapid oxidation of solid Mn(OH)2 to Mn(OH)3 in alkaline medium. When acidified, the Mn (III) readily releases iodine from iodide. A 240.-mL water sample, in a stoppered vessel, was treated with 1.10 mL of a concentrated solution of NaI and NaOH and 1.10 mL of a manganese(II) solution. Oxidation of the Mn(OH)2 was complete in about 1 min. The precipitates were then dissolved by addition of 2.20 mL of concentrated H2SO4, whereupon an amount of iodine equivalent to the Mn(OH)3 (and hence to the dissolved O2) was liberated. A 24.5-mL aliquot (of the 244 mL) was titrated with 14.2 mL of 0.00861 M thiosulfate. Calculate the mass in milligrams of O2 per milliliter sample. Assume that the concentrated reagents are O2 free and take their dilutions of the sample into account.

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14a. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize...

14a. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP.
How many grams of KHP are needed to exactly neutralize 22.3 mL of a 0.504 M calcium hydroxide solution ?
_______grams KHC8H4O4

14b. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP.
What volume of a 0.561 M barium hydroxide solution is needed to exactly neutralize 5.17 grams of KHP ?
_____mL barium hydroxide

14c. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP.
If 2.62 grams of KHP are needed to exactly neutralize 25.9 mL of a potassium hydroxide solution, what is the concentration of the base solution ?
_______M potassium hydroxide

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A sheet of gold weighing 12.0 g and at a temperature of 20.0°C is placed flat...

A sheet of gold weighing 12.0 g and at a temperature of 20.0°C is placed flat on a sheet of iron weighing 21.5 g and at a temperature of 59.4°C. What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings.

A 34.51−g stainless steel ball bearing at 104.89 °C is placed in a constant-pressure calorimeter containing 116.9 g of water at 22.47°C. If the specific heat of the ball bearing is 0.474 J / (g ·°C)calculate the final temperature of both the water and steel when they equilibrate. Assume the calorimeter to have negligible heat capacity.

A quantity of 2.00 ×102 mL of 0.641 M HCl is mixed with 2.00 ×102 mL of 0.321 M Ba(OH)2 in a constant-pressure calorimeter of negligible heat capacity. The initial temperature of the HCl and Ba(OH)2 solutions is the same at 21.87°C. For the process below, the heat of neutralization is −56.2 kJ/mol. What is the final temperature of the mixed solutions?

H+(aq) + OH(aq) → H2O(l)

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A) Calculate the mass defect of the helium nucleus 52He. The mass of neutral 52He is...

A) Calculate the mass defect of the helium nucleus 52He. The mass of neutral 52He is given by MHe=5.012225amu. Answer in amu

B) Calculate the binding energy E of the helium nucleus 52He (1eV=1.602×10−19J). Answer in Mev

C) Calculate the binding energy per nucleon of the helium nucleus 52He. Answer in MeV

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Hydrazine, N 2 H 4 , reacts with oxygen to form nitrogen gas and water. N...

Hydrazine, N 2 H 4 , reacts with oxygen to form nitrogen gas and water. N 2 H 4 ( aq ) + O 2 ( g ) ⟶ N 2 ( g ) + 2 H 2 O ( l ) If 2.45 g of N 2 H 4 reacts with excess oxygen and produces 0.650 L of N 2 , at 295 K and 1.00 atm, what is the percent yield of the reaction?

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Although the formula of this new chemical is a trade secret, it can be revealed that...

Although the formula of this new chemical is a trade secret, it can be revealed that the formula for Herbigon is X-acetate (XCH3COO, where "X" represents the top-secret cation of the salt). It is this cation that kills weeds. Since it is critical to have Herbigon dissolved (it won't kill weeds as a suspension), you are working on adjusting the pH so Herbigon will be soluble at the concentration needed to kill weeds. What pH must the solution have to yield a solution in which the concentration of X+ is 3.50×10−3M ? The pKa of acetic acid is 4.76.

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what is the molar concentration of 2-methylbutanol in its neat solution?

what is the molar concentration of 2-methylbutanol in its neat solution?

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1) Determine the volume (liters) of 0.500 M NaOH solution required to neutralize 1.75 L of...

1) Determine the volume (liters) of 0.500 M NaOH solution required to neutralize 1.75 L of 0.250 M H2SO4. The neutralization reaction is: H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2 H2O (l) Determine the volume (liters) of 0.500 M NaOH solution required to neutralize 1.75 L of 0.250 M H2SO4. The neutralization reaction is: H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2 H2O (l) 7.00 0.875 1.75 0.438 none of the above

2) How many moles of HNO3 are present if 7.80×10−2 mol of Ba(OH)2 was needed to neutralize the acid solution? Express your answer with the appropriate units.

3)What is the final volume in milliliters when 0.919 L of a 41.5 % (m/v) solution is diluted to 21.8 % (m/v)?

please help with these problems and please show me how you got the answer

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What important physical chemical property of drug polymorph strictures dictates whether a particular polymorph will be...

What important physical chemical property of drug polymorph strictures dictates whether a particular polymorph will be viable as a marketed therapuetic agent? There are multiple such properties but think about the example given in the manual that highlights what is probably the most important property.

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A 1.20-L contains 1.10 g of an unknown gas at STP . what is the molecular...

A 1.20-L contains 1.10 g of an unknown gas at STP . what is the molecular weight of the unknown gas?

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Which of the following will increase the amount of product present at equilibrium for the reaction:...

Which of the following will increase the amount of product present at equilibrium for the reaction: 2A(g) B(g) AH 84 and K 1.3 x 103. (Chhose all correct answers) A) decrease the temperature B) decrease the volume of the reactino vessel C) Increase the temperature D) add a catalyst E) Increase the pressure by adding argon F) increase the pressure of A G) increase the volume of the reaction vesse

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