Questions
A 5.65 −g sample of a weak acid with Ka=1.3×10−4 was combined with 5.20 mL of...

A 5.65 −g sample of a weak acid with Ka=1.3×10−4 was combined with 5.20 mL of 5.90 M NaOH and the resulting solution was diluted to 750 mL. The measured pH of the solution was 4.30. What is the molar mass of the weak acid?

**please show work

In: Chemistry

Discuss the most important factors that influence the oxidation processes of sulphide minerals. Use the relevant...

Discuss the most important factors that influence the oxidation processes of sulphide minerals. Use the relevant equations/information whenever it is appropriate. (maximum 250 words)

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Iron (III) ion and thiocyanate ion exists in equilibrium with iron thiocyanate ion. The reaction, as...

Iron (III) ion and thiocyanate ion exists in equilibrium with iron thiocyanate ion. The reaction, as written, is exothermic. Given that the FeNCS2+
product is a deep red color and the reactants are nearly colorless, which of the following will cause the solution to bedarker in color at equilibrium?
Fe3+(aq) + NCS(aq) ↔ FeNCS2+(aq)

Increasing the solution temperature

Adding FeNO3

Removing Fe3+ ion by adding NaOH which reacts with Fe3+ ion.

Removing NCS ion by adding AgNO3 with reactacts with NCS ion.

None of these

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1) Cyclopropane, a substance used with oxygen as a general anesthetic, contains only two elements, carbon...

1) Cyclopropane, a substance used with oxygen as a general anesthetic, contains only two elements, carbon and hydrogen. When 1.00 g of this substance is completely combusted, 3.14 g of CO2 and 1.29 g of H2O are produced. What is the empirical formula of cyclopropane?

2) Isobutyl propionate is the substance that provides the flavor for rum extract. Combustion of a 1.152 g sample of this carbon-hydrogen-oxygen compounds yields 2.726 g CO2 and 1.116 g H2O. What is the empirical formula of isobutyl propionate?

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why studying the Stereophysical organic chemistry? please give me 3 reasons

why studying the Stereophysical organic chemistry? please give me 3 reasons

In: Chemistry

In the Chemical Equilibrium experiment, the effect of interacting equilibria was studied using the following chemical...

In the Chemical Equilibrium experiment, the effect of interacting equilibria was studied using the following chemical reactions. Addition of which species will cause the primary equilibrium to shift to the right? Select any/all that apply.

Primary Equilibrium: Fe3+(aq) + SCN-(aq) ⇌ [Fe(SCN)]2+(aq)

Interactive Equilibria: Fe3+(aq) + 3OH-(aq) ⇌ Fe(OH)3(s)

Fe3+(aq) + 3C2O42-(aq) ⇌ [Fe(C2O4)3]3-(aq)

Ag+(aq) + SCN-(aq) ⇌ AgSCN(s)

1 OH-(aq)

2 SCN-(aq)

3 [Fe(SCN)]2+

4 Ag+(aq)

5 Fe3+(aq)

6 C2O42-(aq)

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A chemist fills a reaction vessel with 1.54 atm nitrogen N 2 gas, 4.42 atm oxygen...

A chemist fills a reaction vessel with 1.54 atm nitrogen N 2 gas, 4.42 atm oxygen O 2 gas, and 8.99 atm nitrogen monoxide NO gas at a temperature of 25.0 ° C . Under these conditions, calculate the reaction free energy Δ G for the following chemical reaction: + N 2 g O 2 g 2 NO g Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. kJ

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A mixture of 0.05263 mol of H2O, 0.01327 mol of CH4, 0.07198 mol of CO, and...

A mixture of 0.05263 mol of H2O, 0.01327 mol of CH4, 0.07198 mol of CO, and 0.06917 mol of H2 is placed in a 1.0-L steel pressure vessel at 1303 K.

The following equilibrium is established: 1 H2O(g) + 1 CH4(g) 1 CO(g) + 3 H2(g) At equilibrium 0.009871 mol of CH4 is found in the reaction mixture.

(a) Calculate the equilibrium partial pressures of H2O, CH4, CO, and H2.

Peq(H2O) = .

Peq(CH4) = .

Peq(CO) = .

Peq(H2) = .

(b) Calculate KP for this reaction. KP = ?

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At 35oC, K = 1.6 x 10-5 for the following reaction 2NOCl(g) <----> 2NO(g) +   ...

At 35oC, K = 1.6 x 10-5 for the following reaction

2NOCl(g) <----> 2NO(g) +    Cl2(g)

Calculate the concentration of all species at equilibrium for each of the following original mixtures.

1) 3.0 moles of pure NOCl in a 2.0 L flask

2) 2.0 moles of NOCl and 2 moles of NO in a 3 L flask

3) 3.0 moles of NOCl 1 mole of Cl2 in a 2.0 L flask

Show work please

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Find the net ionic reaction (precipitation). Write NR if there is no reaction. (AlCl3 + KI)...

Find the net ionic reaction (precipitation). Write NR if there is no reaction.

(AlCl3 + KI)

(Zn(C2H3O2)2 + KI)

(AlCl3 + AgNO3)

(Zn(C2H3O2)2 + AgNO3)

(AlCl3 + Na2CO3)

(Zn(C2H3O2)2 + Na2CO3)

(AlCl3 + NaOH)

(Zn(C2H3O2)2 + NaOH)

(AlCl3 + Na3PO4)

(Zn(C2H3O2)2 + Na3PO4)

(AlCl3 + Pb(NO3)2)

(Zn(C2H3O2)2 + Pb(NO3)2)

(CuSO4 + (Zn(C2H3O2)2)

(AlCl3 + (Zn(C2H3O2)2)

(CuSO4 + AlCl3)

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Describe the nature of “random error” and “systematic error”. Provide three examples for each of these...

Describe the nature of “random error” and “systematic error”. Provide three examples for each of these two categories of errors. Could they be eliminated and how?

In: Chemistry

What is denitrification in the context of ozone depletion, and why is it important? Group of...

What is denitrification in the context of ozone depletion, and why is it important?

Group of answer choices

a) Denitrification is the significant lowering of the concentration of N2 (g) in the stratosphere. This process is crucial to ozone formation, as it creates space in the stratosphere for formed ozone to reside.

b) Denitrification is the removal of NO2 (g) from the stratosphere. This process increases ozone depletion, since it prevents ClO (g) from being stored as catalytically inactive ClONO2 (g)

c) Denitrification is removal of NO (g) from the stratosphere. This is important because NO can act as a significant X catalyst and drive ozone depletion.

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A) A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to...

A) A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to determine its Ksp at 25 °C. The endpoint was reached when 55.00 mL of the manganese(II) hydroxide solution was titrated with 2.55 mL of 0.0050 M HCl solution. What is the Ksp of manganese(II) hydroxide?

B) What is the approximate concentration of free Ag+ ion at equilibrium when 1.86×10-2 mol silver nitrate is added to 1.00 L of solution that is 1.330 M in S2O32-. For [Ag(S2O3)2]3-, Kf = 2.9×1013.

C) What is the approximate concentration of free Cd2+ ion at equilibrium when 1.15×10-2 mol cadmium(II) nitrate is added to 1.00 L of solution that is 1.330 M in CN-. For [Cd(CN)4]2-, Kf = 6.0×1018.

D) What is the approximate concentration of free Ag+ ion at equilibrium when 1.72×10-2 mol silver nitrate is added to 1.00 L of solution that is 1.330 M in CN-. For [Ag(CN)2]-, Kf = 1.3×1021.

(I don't know what needs to be updated? This is the question)

In: Chemistry

The following are at constant T and P. The conditions described in (a) and (b) below...

The following are at constant T and P. The conditions described in (a) and (b) below are initial conditions. Calculate Qc and CLEARLY indicate, with an arrow (“?”, or “?”) to which side the reaction must shift in order to attain equilibrium.

(a) A 250.0-mL flask containing 0.0250 mol of NO(g), 0.0100 mol of Cl2(g), and 0.250 mol of

NOCl: 2NO(g) + Cl2(g) ⇌ 2NOCl(g) Kc = 4.6 × 104

(b) A 5.00-L flask containing 35.0 g of NH3, 20.0 g of N2, and 15.5 g of H2:

N2(g) + 3H2(g) ⇌ 2NH3(g) Kc = 0.060

(show work)

DIRECTION OF SHIFT    Value of Qc

(a) __________________ __________

(b) __________________ __________

In: Chemistry

E. coli asparate transcarbamoylase (ATCase) has a Hill coefficient of 1.7 and Vmax 4.5 uM/min. The...

E. coli asparate transcarbamoylase (ATCase) has a Hill coefficient of 1.7 and Vmax 4.5 uM/min. The definition of Vmax is Kcat * [Etot], where kcat is the rate constant for formation of product. The measured value of kcat for this reaciton, which is determined in the absence of CTP, is 800 1/min. The dissociation constant for the allosteric effector CTP from ATCase is 1 mM. When CTP is bound to ATCase the K(1/2) for asparate is 20 mM; when CTP is not bound to ATCase the K(1/2) for asparate is 5 mM.

a) Calculate what the concentration of total ATCase is under the conditions where Vmax was determined. Calculate how much ATCase is present with CTP bound and how much is present without CTP bound when the CTP concentration is 6 mM. Calculate how much ATCase is present with CTP bound and how much is present without CTP bound when the CTP concentration is 0.3 mM.

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