A mixture of 0.05263 mol of H2O, 0.01327 mol of CH4, 0.07198 mol of CO, and...

A mixture of 0.05263 mol of H2O, 0.01327 mol of CH4, 0.07198 mol of CO, and 0.06917 mol of H2 is placed in a 1.0-L steel pressure vessel at 1303 K.

The following equilibrium is established: 1 H2O(g) + 1 CH4(g) 1 CO(g) + 3 H2(g) At equilibrium 0.009871 mol of CH4 is found in the reaction mixture.

(a) Calculate the equilibrium partial pressures of H2O, CH4, CO, and H2.

Peq(H2O) = .

Peq(CH4) = .

Peq(CO) = .

Peq(H2) = .

(b) Calculate KP for this reaction. KP = ?

Solutions

Expert Solution

Hope you will like my answer:)

queen_honey_blossom answered 3 months ago

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