Question

In: Chemistry

K CONSTANT EQUILIBRIUM What does it mean when K=1 and when K= 0

K CONSTANT EQUILIBRIUM

What does it mean when K=1 and when K= 0

Solutions

Expert Solution

When K = 1 it means amount of reactants and products will be the same or intermediate i.e reaction is in equilibrium condition.

Let's take an example to understand in easy way

suppose a reaction:

aA + bB —> cC+ dD

so, the equilibrium constant for the above reaction is,

K = [C]c [D]d/[A]a [B]b

but when K = 1

it means 1 =  [C]c [D]d/[A]a [B]b

   [A]a [B]b =  [C]c [D]d

Therefore, from the above equation we can see that amount of reactants is same as the amount of products i.e. reaction is in equilibrium condition.

And when K = 0 it means reaction is not proceed or we can say that the formation of product is zero.

Let's take an example

the reaction is :

aA + bB —> cC+ dD

so, the equilibrium constant for the above reaction is,

K = [C]c [D]d/[A]a [B]b

but when K = 0

it means the product term is zero that's by K is 0.

So from above the equation we can say that reaction is not proceed or amount of product is 0.

Thank You


Related Solutions

1.The equilibrium constant of a reversible process at 386 K is 9.2, what is the standard...
1.The equilibrium constant of a reversible process at 386 K is 9.2, what is the standard change in free energy for that process? 2.   What is the reaction order for a process whose rate constant has units of M-3 s-1? 3.   The standard molar entropy of solid iron at 298 K is 27.2 J/mol.K. How many microstates are associated with 50 atoms of iron at this temperature? 5.   What is the pH of the solution that is formed when 10.0 grams of magnesium...
When Economic Profit = 0, then what does this mean? 1-This means that all firms are...
When Economic Profit = 0, then what does this mean? 1-This means that all firms are operating at a loss. The best thing to do next would be to raise prices to cover the losses. 2-There is no motivation for the firms to leave the industry and there is no motivation for new firms to enter the industry. 3-Everyone run for the exit doors! Everyone in the industry is crazy if they don’t get out of an industry like this...
1)The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) The equilibrium...
1)The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <------ ------> PCl3(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PCl5(g) is introduced into an evacuated flask at a pressure of 1.14 atm at 500 K. PPCl5 = atm PPCl3 = atm PCl2 = atm 2) The equilibrium constant, Kp, for the following reaction is 55.6 at 698...
what is a mixed strategy nash equilibrium and what does it mean when a player has...
what is a mixed strategy nash equilibrium and what does it mean when a player has a dominated strategy
What does it mean when stated, By changing the sign of the gravitational constant, the work...
What does it mean when stated, By changing the sign of the gravitational constant, the work on the object also becomes positive or negative.
The equilibrium constant for the reaction below is K = 0.36 at 400 K. If 1.5...
The equilibrium constant for the reaction below is K = 0.36 at 400 K. If 1.5 g of PCl5 was initially placed in a reaction vessel with a volume of 250 cm3, what is the molar concentration of each gas at equilibrium? What is Delta Gorxn for the reaction: PCl5 (g) à PCl3 (g) + Cl2 (g) - Please show all work.
Consider the equilibrium N2(g) + O2(g) ⇄ 2 NO(g) At 2300 K the equilibrium constant K...
Consider the equilibrium N2(g) + O2(g) ⇄ 2 NO(g) At 2300 K the equilibrium constant K = 1.7 × 10-3. Suppose that 0.0150 mol NO(g), 0.250 mol N2(g), and 0.250 mol O2(g) are placed into a 10.0-L flask and heated to 2300 K. The system is not at equilibrium. Determine the direction the reaction must proceed to reach equilibrium and the final equilibrium concentrations of each species. to the right to the left [N2] =____ mol/L [O2] = ____mol/L [NO]...
1) The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) <---...
1) The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) <--- ---> CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains  0.206 M  COCl2, 5.16×10-2 M CO and 5.16×10-2M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.88×10-2 mol of CO(g) is added to the flask? [COCl2] = M [CO] = M [Cl2] = M 2) The equilibrium constant,...
1) The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) <-----...
1) The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) <----- ------> PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.201 M PCl5, 4.91×10-2 M PCl3 and 4.91×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.27×10-2 mol of Cl2(g) is added to the flask? [PCl5] = M [PCl3] = M [Cl2] = M 2)...
1) The equilibrium constant, K, for the following reaction is 2.02×10-2 at 513 K. PCl5(g) <------...
1) The equilibrium constant, K, for the following reaction is 2.02×10-2 at 513 K. PCl5(g) <------ ------> PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 18.3 L container at 513 K contains 0.216 M PCl5, 6.60×10-2 M PCl3 and 6.60×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 8.25 L? [PCl5] = ______M [PCl3] =...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT