Question
In: Statistics and Probability
The cholesterol levels of an adult can be described by a normal model with a mean...
The cholesterol levels of an adult can be described by a normal model with a mean of 188 mg/dL and a standard deviation of 26
b) What percent of adults do you expect to have cholesterol levels over
190mg/dL?
(Round to two decimal places as needed.)
c) What percent of adults do you expect to have cholesterol levels between
160 and 170 mg/dL?
(Round to two decimal places as needed.)
d) Estimate the interquartile range of cholesterol levels.
IQRequals=
(Round to the nearest integer as needed.)
e) Above what value are the highest 15% of adults' cholesterol levels?
(Round to the nearest integer
Solutions
orchestra answered 1 year agoRelated Solutions
The cholesterol levels of an adult can be described by a normal model with a mean...
The cholesterol levels of an adult can be described by a normal
model with a mean of 187 mg/dL and a standard deviation of 28
What percent of adults do you expect to have cholesterol levels
over 210 mg/dL? (round two decimal places)
c) What percent of adults do you expect to have cholesterol
levels between 150 and 160 mg/dL?(round two decimal places)
d) Estimate the interquartile range of cholesterol levels.
IQR= ____ (round to nearest integer)
e)Above what value...
2. Assume the cholesterol levels of adult American women can be described by a Normal distribution...
2. Assume the cholesterol levels of adult American women can be
described by a Normal distribution with a mean of 196 mg/dL and a
standard deviation of 27 mg/dL.
a) What percent of adult women do you expect to have cholesterol
levels over 200 mg/dL
b)
Whatpercentofadultwomendoyouexpecttohavecholesterollevelsbetween170and200
mg/dL?
c) Above what value are the highest 15% of women’s cholesterol
levels?
d) What cholesterol level represents the 98th percentile?
The prices of pizzas can be described by a normal model with a mean of $12...
The prices of pizzas can be described by a normal model with a
mean of $12 and
a standard deviation of $3.
12. Draw the model showing the 68-95-99.7 Rule
13. Use the 68-95-99.7 Rule to estimate the proportion of
pizzas with prices
between $12 and $18
14. Use the 68-95-99.7 Rule to estimate the proportion of
pizzas with prices less
than $9
15. Use the 68-95-99.7 Rule to estimate the proportion of
pizzas with prices more than $21
The distribution of cholesterol levels in a boy is approximately normal with a mean of 170...
The distribution of cholesterol levels in a boy is approximately
normal with a mean of 170 and a standard deviation of 30. Levels
above 200 require attention. What is the probability of a boy with
a cholesterol between 160 and 205?
Assume that the duration of human pregnancies can be described by a Normal model with mean...
Assume that the duration of human pregnancies can be described
by a Normal model with mean 267 days and standard deviation 14
days.
a) What percentage of pregnancies should last between 272 and
284 days?
b) At least how many days should the longest 20%of all
pregnancies last?
c) Suppose a certain obstetrician is currently providing
prenatal care to 60 pregnant women. Let y
represent the mean length of their pregnancies. According to the
Central Limit Theorem, what's the distribution...
Assume that the duration of human pregnancies can be described by a normal model with mean...
Assume that the duration of human pregnancies can be described
by a normal model with mean 266 days and standard deviation 15
days. Complete parts a) through d) below.
a) What percentage of pregnancies should last between 265 and
270 days? % (Round to one decimal place as needed.)
b) At least how many days should the longest 30% of all
pregnancies last? P(X greater than or equals nothing)=0.30
(Round to one decimal place as needed.)
c) Suppose...
Assume that the duration of human pregnancies can be described by a Normal model with mean...
Assume that the duration of human pregnancies can be described
by a Normal model with mean 266266 days and standard deviation 1818
days. a) What percentage of pregnancies should last between 268268
and 276276 days? b) At least how many days should the longest
3030% of all pregnancies last? c) Suppose a certain obstetrician
is currently providing prenatal care to 6868 pregnant women. Let y
overbary represent the mean length of their pregnancies. According
to the Central Limit Theorem, what's...
Assume that the duration of human pregnancies can be described by a normal model with mean...
Assume that the duration of human pregnancies can be described
by a normal model with mean 266 days and standard deviation 12
days. Complete parts
a) What percentage of pregnancies should last between 275 and
280 days? _________%
(Round to one decimal place as needed.)
b) At least how many days should the longest 30% of all
pregnancies last?
P(X greater than or equals≥________)=0.30
(Round to one decimal place as needed.)
c) Suppose a certain obstetrician is currently providing
prenatal...
Assume that the duration of human pregnancies can be described by a Normal model with mean...
Assume that the duration of human pregnancies can be described
by a Normal model with mean 268 days and standard deviation 16
days. a) What percentage of pregnancies should last between 274
and 285 days? b) At least how many days should the longest 15%
of all pregnancies last? c) Suppose a certain obstetrician is
currently providing prenatal care to 51 pregnant women. Let y
overbar represent the mean length of their pregnancies. According
to the Central Limit Theorem, what's...
Assume that the duration of human pregnancies can be described by a Normal model with mean...
Assume that the duration of human pregnancies can be described
by a Normal model with mean 268 days and standard deviation 14
days.
a) What percentage of pregnancies should last between 274 and
281 days? (Round to two decimal places as needed.)
b) At least how many days should the longest 25% of all
pregnancies last? (Round to one decimal place as needed.)
c) Suppose a certain obstetrician is currently providing
prenatal care to 58 pregnant women. Let y overbar...
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