In: Statistics and Probability
An automotive repair shop has determined that the average service time on an automobile is 2 hours with a standard deviation of 30 minutes. A random sample of 36 services is selected. (a) What is the probability that the sample of 36 will have a mean service time greater than 115 minutes? (b) Assume the population consists of 400 services. Determine the standard error of the mean.
Solution:
Given: An automotive repair shop has determined that the average service time on an automobile is 2 hours with a standard deviation of 30 minutes.
For two hours, number of minutes = 2 X 60 = 120 minutes.
Thus Mean number of minutes = = 120 and standard deviation =
Sample size = n = 36
Part a) Find the probability that the sample of 36 will have a mean service time greater than 115 minutes
That is:
Find z score :
Thus we get:
Look in z table for z = -1.0 and 0.00 and find area.
P( Z < -1.00) = 0.1587
Thus
Thus the probability that the sample of 36 will have a mean service time greater than 115 minutes is 0.8413
Part b) the population consists of 400 services. That is : n = 400
We have to determine the standard error of the mean.
It is given by formula:
Thus the standard error of the mean is