In: Statistics and Probability
You may need to use the appropriate appendix table to answer this question.
Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile repair is normally distributed with a standard deviation of $88. Answer the following questions about the cost of automobile repairs.
(a) What is the probability that the cost will be more than $490? (Round your answer to four decimal places.)
(b) What is the probability that the cost will be less than $290? (Round your answer to four decimal places.)
(c) What is the probability that the cost will be between $290 and $490? (Round your answer to four decimal places.)
(d) If the cost for your car repair is in the lower 5% of automobile repair charges, what is your maximum possible cost in dollars? (Round your answer to the nearest cent.)
$
Solution :
Given that ,
mean = = $367
standard deviation = = $88
(a)
P(x > $490) = 1 - P(x < 490)
= 1 - P((x - ) / < (490 - 367) / 88)
= 1 - P(z < 1.3977)
= 1 - 0.9189
= 0.0811
Probability = 0.0811
(b)
P(x < $290) = P((x - ) / < (290 - 367) / 88)
= P(z < -0.875)
= 0.1908
Probability = 0.1908
(c)
P($290 < x < $490) = P((290 - 367)/ 88) < (x - ) / < (490 - 367) / 88) )
= P(-0.875 < z < 1.3977)
= P(z < 1.3977) - P(z < -0.875)
= 0.9189 - 0.1908
= 0.7281
Probability = 0.7281
(d)
Using standard normal table,
P(Z < z) = 5%
P(Z < -1.65) = 0.05
z = -1.65
Using z-score formula,
x = z * +
x = -1.65 * 88 + 367 = 221.8 = 222
maximum possible cost in dollars $222