In: Statistics and Probability
The average starting salary of students who graduated from colleges of Business in 2009 was $48,400. A sample of 100 graduates of 2010 showed an average starting salary of $50,000. Assume the standard deviation of the population is known to be $8000. We want to determine whether or not there has been a significant increase in the starting salaries. Step 1. Statement of the hypothesis (1.5 marks) Step 2. Standardized test statistic formula (1 mark) Step 3. State the level of significance (1 mark) Step 4. Decision Rule (Draw a bell to show rejection zone) Step 5. Calculation of the statistic Step 6. Conclusion (1.5 marks)
Sol:
Step 1. Statement of the hypothesis (1.5 marks)
Null hypothesis:
There is no increase in salary from the hypothesized value of 48400
Ho:Mu=48400
Alternative hypothesis:
There is an increase in salary from the hypothesized value of 48400
Ha:Mu>48400
Step 2. Standardized test statistic formula (1 mark)
z=xbar-mu/sigma/sqrt(n)
xbar=sample mean
mu=population mean
sigma=population standard deviation
n=sample size
Step 3. State the level of significance (1 mark)
alpha=5%=0.05
Step 4.
z crit=NORM.S.INV(0.05)=1.644853627
that z crit ar 5%=1.645
RIght side is critical region
if Zo>1.645,reject Ho
Else accept Ho
Step-5:
z=xbar-mu/sigma/sqrt(n)
z=(50000-48400)/(8000/sqrt(100))
Z=2
Step 6. Conclusion (1.5 marks)
z =2>1.645
Reject Ho
There is sufficient statistical evidence at 5% level of significance to conclude that
there has been a significant increase in the starting salaries