In: Statistics and Probability
answer
A researcher examines factors that affect thinking. In one study, she had three groups of participants work on seven problems that required creative thinking. One group prepared for the task by exercising; a second group watched a comedy video; the third group was a control group that simply began work on the problems. The scores below show the number correct for each participant.
Exercise |
Comedy |
Control |
5 |
4 |
4 |
4 |
7 |
2 |
1 |
2 |
1 |
2 |
5 |
1 |
3 |
3 |
3 |
0 |
4 |
2 |
2 |
1 |
0 |
Select the correct statistical test; perform the test, and any subsequent post-hoc tests; report the results according to the handbook guidelines; explain what the results mean.
Using Excel, go to Data tab, select Data Analysis, choose Anova: Single Factor
ANOVA - Single Factor | ||||||
Alpha | 0.05 | |||||
Groups | Count | Sum | Mean | Variance | ||
Exercise | 7 | 17 | 2.42857142857143 | 2.95238095238095 | ||
Comedy | 7 | 26 | 3.71428571428571 | 3.9047619047619 | ||
Control | 7 | 13 | 1.85714285714286 | 1.80952380952381 | ||
Source of Variation | SS | df | MS | F | P-value | F critical |
Between Groups | 12.6666666666667 | 2 | 6.33333333333333 | 2.19230769230769 | 0.140574263175222 | 3.55455714566179 |
Within Groups | 52 | 18 | 2.88888888888889 | |||
Total | 64.6666666666667 | 20 |
H0: μ1 = μ2 = μ3, Mean scores for the three factors are the same
H1: Mean score for at least one of the three factors is different
p-value (Significance F) = 0.141
Since p-value is more than 0.05, we do not reject the null hypothesis and conclude that mean scores for the three factors are the same. So, all the three factors have same effect on level of thinking.
Since there is no significant difference in means, there is no need to conduct a post-hoc test.