Question

In: Statistics and Probability

Perform a chi-square test to look at the relationship between region of the country (REGION) and...

Perform a chi-square test to look at the relationship between region of the country (REGION) and financial comfort (FCOMFORT). Using alpha = .05, what would you conclude from your test:

a. Financial comfort differs depending on the area one lives in.
b. People living in less expensive areas are more likely to report that they are financially comfortable.
c. There is not a significant relationship between region and financial comfort.

d. People living in the northeast region are most likely to report that they are financially struggling.

From SPSS

Case Processing Summary

Cases

Valid

Missing

Total

N

Percent

N

Percent

N

Percent

Financial Comfort * US Region

400

100.0%

0

0.0%

400

100.0%

Financial Comfort * US Region Crosstabulation

Count

US Region

New England

N. East

Mid Atlantic

S East

Great Lakes

N Central

Financial Comfort

Comfortable

14

16

21

37

19

14

Struggling

14

19

15

26

13

13

Total

28

35

36

63

32

27

Chi-Square Tests

Value

df

Asymptotic Significance (2-sided)

Pearson Chi-Square

3.378a

9

.947

Likelihood Ratio

3.381

9

.947

Linear-by-Linear Association

.000

1

.983

N of Valid Cases

400

Solutions

Expert Solution

Expected frequency of a cell = sum of row*sum of column / total sum
Expected Frequencies
Total
Comfort 28*121/221=15.33 35*121/221=19.163 36*121/221=19.71 63*121/221=34.493 32*121/221=17.52 27*121/221=14.783 121
Struggling 28*100/221=12.67 35*100/221=15.837 36*100/221=16.29 63*100/221=28.507 32*100/221=14.48 27*100/221=12.217 100
Total 28 35 36 63 32 27 221
(fo-fe)^2/fe
Comfort 0.115 0.522 0.084 0.182 0.1250 0.0415
Struggling 0.140 0.632 0.102 0.220 0.1512 0.0502

Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =   2.366

Level of Significance =   0.05                          
Number of Rows =   2                          
Number of Columns =   6                          
Degrees of Freedom=(#row - 1)(#column -1) = (2- 1 ) * ( 6- 1 ) =   5                          
                              
p-Value =   0.7966   [Excel function: =CHISQ.DIST.RT(χ²,df) ]                      
Decision:    p value > α , do not reject Ho                          

which means relationship is not significant and hence

c. There is not a significant relationship between region and financial comfort.

Thanks in advance!

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