In: Statistics and Probability
Perform a chi-square test to look at the relationship between
region of the country (REGION) and financial comfort (FCOMFORT).
Using alpha = .05, what would you conclude from your test:
a. Financial comfort differs depending on the area one lives
in.
b. People living in less expensive areas are more likely to report
that they are financially comfortable.
c. There is not a significant relationship between region and
financial comfort.
d. People living in the northeast region are most likely to report that they are financially struggling.
From SPSS
Case Processing Summary |
||||||
Cases |
||||||
Valid |
Missing |
Total |
||||
N |
Percent |
N |
Percent |
N |
Percent |
|
Financial Comfort * US Region |
400 |
100.0% |
0 |
0.0% |
400 |
100.0% |
Financial Comfort * US Region Crosstabulation |
||||||||||||
Count |
||||||||||||
US Region |
||||||||||||
New England |
N. East |
Mid Atlantic |
S East |
Great Lakes |
N Central |
|||||||
Financial Comfort |
Comfortable |
14 |
16 |
21 |
37 |
19 |
14 |
|||||
Struggling |
14 |
19 |
15 |
26 |
13 |
13 |
||||||
Total |
28 |
35 |
36 |
63 |
32 |
27 |
Chi-Square Tests |
|||
Value |
df |
Asymptotic Significance (2-sided) |
|
Pearson Chi-Square |
3.378a |
9 |
.947 |
Likelihood Ratio |
3.381 |
9 |
.947 |
Linear-by-Linear Association |
.000 |
1 |
.983 |
N of Valid Cases |
400 |
Expected frequency of a cell = sum of row*sum of column / total sum | |||||||
Expected Frequencies | |||||||
Total | |||||||
Comfort | 28*121/221=15.33 | 35*121/221=19.163 | 36*121/221=19.71 | 63*121/221=34.493 | 32*121/221=17.52 | 27*121/221=14.783 | 121 |
Struggling | 28*100/221=12.67 | 35*100/221=15.837 | 36*100/221=16.29 | 63*100/221=28.507 | 32*100/221=14.48 | 27*100/221=12.217 | 100 |
Total | 28 | 35 | 36 | 63 | 32 | 27 | 221 |
(fo-fe)^2/fe | ||||||
Comfort | 0.115 | 0.522 | 0.084 | 0.182 | 0.1250 | 0.0415 |
Struggling | 0.140 | 0.632 | 0.102 | 0.220 | 0.1512 | 0.0502 |
Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =
2.366
Level of Significance = 0.05
Number of Rows = 2
Number of Columns = 6
Degrees of Freedom=(#row - 1)(#column -1) = (2- 1 ) * ( 6- 1 )
= 5
p-Value = 0.7966 [Excel function:
=CHISQ.DIST.RT(χ²,df) ]
Decision: p value > α , do not reject
Ho
which means relationship is not significant and hence
c. There is not a significant relationship between region and financial comfort.
Thanks in advance!
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