In: Math
Use the following data to conduct a Chi-square test
for each region of the company in the same manner you viewed in the
video:
RegionExpected
Actual
Southeast
Defined
10098
Open
100104Northeast
Defined
150188
Open
150214Midwest
Defined
125120
Open
125108Pacific
Defined
200205
Open
200278
Step 3:
Write an 800–1,000-word essay, utilizing APA
formatting, to discuss the following:
Describe why hypothesis testing is important to
businesses.
Report your findings from each Chi-square test that
you conducted.
Based solely on the Chi-square test, discuss whether
the company should accept the null hypothesis in each region or
reject it in favor of the alternate hypothesis.
Discuss any other statistical analyses you would want
the company to contemplate before deciding if it will go with a
defined or open sales strategy.
Describe and discuss at least 1 other business
scenario in which you believe Chi-square testing would be
h
Answer:
a)
Here we can say that hypothesis testing is utilized to investigate the connection between at least two factors in a test setting. Business directors utilize the consequences of a speculation test when settling on the board choices.
The hypothesis testing enables chiefs to look at circumstances and end results before settling on a urgent administration choice.
Example:
b)
Chi Square = ?(Oij – Eij)^2/Eij ----------->(eq(1))
Where as,
Oij is the watched worth and Eij is the normal worth.
Henceforth,
For South east
After substituting the known values south east in equation (1)
Chi Square = (98-100)^2/100 + (104-100)2/100
Chi Square for south east = 0.2
For Upper east
After substituting the known values for upper east in equation (1)
Chi Square = (188-150)2/150 + (214-150)2/150
Chi square for upper east = 36.93
For Midwest
After substituting the known values for mid west in equation (1)
Chi Square = (120-125)2/125 + (108-125)2/125
Chi Square for mid west = 2.512
For Pacific
After substituting the known values for pacific in equation (1)
Chi Square = (205-200)2/200 + (278-200)2/200
Chi Square for pacific = 30.545
c)
Alpha = 0.05
Accepting there are 2 gatherings for every district
degree of freedom = (r-1)*(c-1)
= (2-1)*(2-1)
= 1*1
df = 1
Chi Square Critical = 3.84
Choice Rule:
On the off chance that Chi Square > Chi Square Critical reject the invalid speculation
Subsequently,
For the South east
Chi Square < Chi Square Critical neglect to dismiss the invalid theory.
For the upper east
Chi Square > Chi Square Critical reject the invalid theory for Alternate Hypothesis
For the mid west
Chi Square < Chi Square Critical neglect to dismiss the invalid theory.
For the pacific
Chi Square > Chi Square Critical reject the invalid theory for Alternate Hypothesis.
d)
The organization ought to likewise consider doing the connection test between the two factors to check for affiliation.
e)
The chi-square trial of freedom can be utilized to confirm the impact of sex on buy choices.
Are men the essential leaders with regards to acquiring an expensive things? Is sexual orientation a factor in shading inclination of a vehicle?
Here factor X would be sexual orientation and variable Y would be shading.