Question

You will perform a Chi-Square test and an ANOVA test. For each hypothesis test make sure to report the following steps:

Identify the null hypothesis, Ho, and the alternative hypothesis, Ha.

Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed.

Find the critical value(s) and identify the rejection region(s).

Find the appropriate standardized test statistic. If convenient, use technology.

Decide whether to reject or fail to reject the null hypothesis.

Interpret the decision in the context of the original claim.

1. A researcher wants to determine whether the time spent online per day is related to gender. A random sample of 315 adults was selected and the results are shown below. Test the hypothesis that the time spent online per day is related to gender. Use α = 0.05.

Resource: The Chi-Square, Independence

Gender	Time spent online per day (minutes)
	0-30	30-60	60-90	90+
Male	25	35	75	45
Female	30	45	45	15

Answer 1

H0: Null Hypothesis: The time spent online per day is not related to gender

HA: Alternative Hypothesis: The time spent online per day is related to gender.

Observed Frequencies

                0- 30             30- 60            60 - 90               90 +                Total

Male            25             35                   75                         45                 180

Female       30             45                    45                         15                  135

Total           55              80                  120                       60                   315

Assuming H0, the expected frequencies are got as follows:

              0 - 30           30 - 60               60 - 90                  90 +             Total

Male    55 X 180/315=31.43       45.71                68.57                 34.29               180

Female    23.57                           34.29                51.43                 25.71                135

Total        55                                  80                  120                      60                   315

O                      E                       (O - E)²/E

25                     31.43                 1.31

35                     45.71                   2.51

75                       68.57                0.60

45                     34.29                   3.35

30                     23.57                  1.75

45                     34.29                  3.35

45                      51.43                 0.80

15                       25.71                 4.46

-----------------------------------------------------

                                     =        18.1463

Degrees of Freedom = (r-1) X (c -1) = (2 - 1) X(4-1)= 3

By Technology, P-value = 0.00041

Since p-value is less than , Reject H0.

The data suppoer the claim that the time spent online per day is related to gender.