Question

In: Physics

a) An electron with 10.0 eV kinetic energy hits a 10.1 eV potential energy barrier. Calculate...

a) An electron with 10.0 eV kinetic energy hits a 10.1 eV potential energy barrier. Calculate the penetration depth.

b) A 10.0 eV proton encountering a 10.1 eV potential energy barrier has a much smaller penetration depth than the value calculated in (a). Why?

c) Give the classical penetration depth for a 10.0 eV particle hitting a 10.1 eV barrier.

Solutions

Expert Solution

(a) The penetration depth is the distance outside the barrier where the wavefunction becomes 1/e of its original value. I am starting this answer from basics for better understanding:

Note: The constant 'h cut' is used here which is (h/2π).

(b) The penetration depth is smaller for proton because proton is much heavier than electron. Since the penetration depth is inversely proportional to the mass, hence penetration depth for proton would be smaller.

(c) Since according to classical physics, the particle with lower energy than barrier would not cross the barrier.Hence there will be no penetration. So it is zero in this case.

Hope you like the answer. Have a nice day .Sorry for any calculation mistake :)


Related Solutions

An electron approaches a 1.30 nm wide potential-energy barrier of height 5.60 eV
An electron approaches a 1.30 nm wide potential-energy barrier of height 5.60 eV. At what energy does the electron have a tunneling probability of10%?
A proton with initial kinetic energy 50.0 eV encounters a barrier of height 70.0 eV. What...
A proton with initial kinetic energy 50.0 eV encounters a barrier of height 70.0 eV. What is the width of the barrier if the probability of tunneling is How does this compare with the barrier width for an electron with the same energy tunneling through a barrier of the same height with the same probability ?
What magnetic field is required to constrain an electron with a kinetic energy of 404 eV...
What magnetic field is required to constrain an electron with a kinetic energy of 404 eV to a circular path of radius 0.777 m?
Electrons in an electron microscope have a kinetic energy of 1.20 105 eV. (a) Find the...
Electrons in an electron microscope have a kinetic energy of 1.20 105 eV. (a) Find the de Broglie wavelength of the electrons. Incorrect: Your answer is incorrect. (b) Find the ratio of this wavelength to the wavelength of light at the middle of the visible spectrum (550 nm). (c) How many times greater magnification is theoretically possible with this microscope than with a light microscope?
a.A free (i.e. unbound) electron has a kinetic energy of 7.5 eV. What is the angular...
a.A free (i.e. unbound) electron has a kinetic energy of 7.5 eV. What is the angular wavenumber of the travelling wave that describes the solution to Schr ̈odinger’s equation for this particle? b.A particle of mass 6.64 × 10-27 kg is confined in an infinite square well of width 2.50 × 10-11 m. It is observed to have an energy of 3.00 eV. How many nodes does its wavefunction have? (Not including those at the walls of the well.) c.What...
POTENTIAL AND KINETIC ENERGY OBJECTIVES: To determine the potential and kinetic energy of a freely falling...
POTENTIAL AND KINETIC ENERGY OBJECTIVES: To determine the potential and kinetic energy of a freely falling body To determine the loss in kinetic energy of an inelastic collision To calculate the percentage error of the experimental error of the velocity of a freely falling body using the conservation of mechanical energy of a body MATERIALS: Tennis balls Digital Timer Meter stick THEORY: Conservation of Mechanical Energy A body raised to a certain height possesses potential energy due to its position....
Calculate the momentum p, kinetic energy K, and total energy E of an electron traveling at...
Calculate the momentum p, kinetic energy K, and total energy E of an electron traveling at each of the speeds tabulated below. v p (keV/c) K (keV) E (keV) (a) 0.03c (b) 0.4c (c) 0.9c
an electron goes from a Betatron accelerator with energy 5 Mev into Copper barrier. calculate :...
an electron goes from a Betatron accelerator with energy 5 Mev into Copper barrier. calculate : 1- at which distance inside the barrier the electron will stop ? 2- as a resultant to this reaction if you detected an emission of a X-Ray , what do you call this rays ?and what it's emitted ratio from electron energy ? ( use drawing as possible )
Give examples of changes of energy from potential to kinetic and from kinetic to potential.
Give examples of changes of energy from potential to kinetic and from kinetic to potential.
The ground state energy of an oscillating electron is 1.24 eV
The ground state energy of an oscillating electron is 1.24 eV. How much energy must be added to the electron to move it to the second excited state? The fourth excited state?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT