Question

def playable(word, hand):

'''Given a word and a hand, check if a word can be made based on the hand you are given.

return True if word can be played or False if no word can be made

hand and False if not. For example:

playable("ZOO", ['Z', 'B', 'O', 'I', 'J', 'O', 'K']) --> True

playable("ELEPHANT", ['H','O',]) --> False

playable("DOG", ['O', 'S', 'Q', 'W', 'O', 'D', 'K']) --> False

playable("ZOOM", ['V', 'M', 'O', 'N', 'Z', 'R', 'D']) --> False.'''

ZOOM is False since missing another O

scrabble code that checks if word is playable based on hand on python

will thumbs up

Answer 1

Python code is pasted below.

#function definition
def playable(str1,list1):
#Taking each character from the string
for char in str1:
#If character is not in string return false
if char not in list1:
return False
#Remove character from list
else:
list1.remove(char)
return True
#main program
#function calling
print(playable("ZOO",["Z","B","O","I","J","O","K"]))
print(playable("ELEPHANT", ['H','O']))
print(playable("DOG", ['O', 'S', 'Q', 'W', 'O', 'D', 'K']))
print(playable("ZOOM", ['V', 'M', 'O', 'N', 'Z', 'R', 'D']))

Python code in IDLE pasted below for better understanding of the indent.

Output Screen