Question

A student is going to take an survey of ten problems. Suppose among the problems that may appear in the exam, the student can solve 20% of them correctly, and 60% partially correctly. If you know that the student can solve exactly three problems in the survey correctly, what is the expected number of problems that he or she can solve partially correctly ?

Find the conditional probability that the student can solve exactly three problems partially correctly given that he or she can solve three problems correctly.

Answer 1

Answer:

Given information:

likelihood for understudy can understand question accurately = 20% = 0.2

likelihood for understudy can explain question Partially effectively = 60% = 0.6

n = absolute number of inquiries.

1)

Expected estimation of understudy can comprehend accurately = n*0.2 = 3

n = 3/0.2

n = 15

Expected estimation of understudy can settle question halfway correctly = n*0.6

Expected estimation of understudy can understand question somewhat correctly = 15*.6

Expected estimation of understudy can understand question mostly correctly = 9

2)

Likelihood for understudy can comprehend precisely 3 inquiries somewhat effectively,

i.e.,

P(PC)= 0.6*0.6*0.6

Likelihood for understudy can comprehend precisely 3 inquiries correctly,

P(C) = 0.2*0.2*0.2

contingent likelihood that the understudy can take care of precisely three issues somewhat accurately given that the individual can take care of three issues correctly.,

P(C|PC) = P(C)/P(PC)

substitute qualities

= (0.2*0.2*0.2)/(0.6*0.6*0.6)

= 0.037

= 3.7%